Answer:
F
Explanation:
Newton's Third Law (Law of Action-Reaction) states:
Every action has an equal and opposite reaction and it occurs between two objects
In this scenario, the action would be the skater pushing off of the wall, therefore the reaction would be the wall pushing off of the skater since the two objects that are interacting are the wall and the skater.
Answer:
Physics extends well into your everyday life, describing the motion, forces and energy of ordinary experience. In actions such as walking, driving a car or using a phone, physics is at work. For everyday living, all the technologies you might take for granted exploit the rules of physics.
Explanation:
Answer:
θ = 12.60°
Explanation:
In order to calculate the angle below the horizontal for the velocity of the hockey puck, you need to calculate both x and y component of the velocity of the puck, and also you need to use the following formula:
(1)
θ: angle below he horizontal
vy: y component of the velocity just after the puck hits the ground
vx: x component of the velocity
The x component of the velocity is constant in the complete trajectory and is calculated by using the following formula:
vo: initial velocity = 28.0 m/s
The y component is calculated with the following equation:
(2)
voy: vertical component of the initial velocity = 0m/s
g: gravitational acceleration = 9.8 m/s^2
y: height
You solve the equation (2) for vy and replace the values of the parameters:
Finally, you use the equation (1) to find the angle:
The angle below the horizontal is 12.60°
The force between the two point charge when they are separated by 18 cm is 3 N
<h3>How do I determine the force when they are 18 cm apart?</h3>
Coulomb's law states as follow:
F = Kq₁q₂ / r²
Cross multiply
Fr² = Kq₁q₂
Kq₁q₂ => constant
F₁r₁² = F₂r₂²
Where
- F₁ and F₂ are the initial and new force
- r₁ and r₂ are the initial and new distance apart
With the above formula, we can obtain the force between the two point charge when they are 18 cm apart. Details below:
- Initial distance apart (r₁) = 6 cm
- Initial force of attraction (F₁) = 27 N
- New distance apart (r₂) = 18 cm
- New force of attraction (F₂) =?
F₁r₁² = F₂r₂²
27 × 6² = F₂ × 18²
972 = F₂ × 324
Divide both side by 324
F₂ = 927 / 324
F₂ = 3 N
Thus, the force when they are 18 cm apart is 3 N
Learn more about force:
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With total velocity 
, the horizontal component of velocity is
Then the horizontal displacement over the first minute is
