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amm1812
4 years ago
10

A slinky is stretched across a classroom and moved up and down at a frequency of 2 hz. if the corresponding wave velocity is 4.2

m s , determine the wavelength of the slinky wave.
Physics
1 answer:
marusya05 [52]4 years ago
4 0
Velocity of a wave is the amount of wavelength multiplied by its frequency. Moreover, derivations would be;wavelength?
Hence wavelength would be velocity divided by the frequency.Result is 2.1 mThank you for your question. Please don't hesitate to ask in Brainly your queries. 
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A jetliner is moving at a speed of 245m/s. The vertical component of the plane's velocity is 40.6 m/s. Determine the magnitude o
Harman [31]

Answer:

Horizontal component of velocity = 241.61 m/s

Explanation:

Given that,

Velocity of a jetliner is 245 m/s

The vertical component of the plane's velocity is 40.6 m/s, v_y=40.6\ m/s

We need to find the magnitude of the horizontal component of the plane velocity.

The resultant velocity is given by :

v=\sqrt{v_x^2+v_y^2}

Where, v_x is the horizontal component of the plane velocity

v^2=v_x^2+v_y^2\\\\v_x^2=v^2-v_y^2\\\\v_x^2=(245)^2-(40.6)^2\\\\v_x=\sqrt{58376.64}\\\\v_x=241.61\ m/s

So, the magnitude of the horizontal component of the plane velocity is 241.61 m/s.

8 0
3 years ago
Which product forms from the synthesis reaction between calcium (Ca) and
cestrela7 [59]

Answer:

CaCl2

Explanation:

5 0
3 years ago
Read 2 more answers
A typical wall outlet voltage in the United States is 120 volts. Personal MP3 players require much smaller voltages, typically 4
alexgriva [62]

Answer:

Number of turns on the secondary coil of the adapter transformer is 10.

Explanation:

For a transformer,

    \frac{V_{s} }{V_{p} } = \frac{N_{s} }{N_{p} }

where V_{s} is the voltage induced in the secondary coil

           V_{p} is the voltage in the primary coil

          N_{s} is the number of turns of secondary coil

         N_{p} is the number of turns of primary coil

From the given question,

    \frac{487*10^{-3} }{120} = \frac{N_{s} }{2464}

⇒    N_{s} = \frac{2462*487*10^{-3} }{120}

            = 9.999733

  ∴   N_{s} = 10 turns

5 0
3 years ago
Read 2 more answers
2) Two railway tracks are parallel to west east direction. Along one track, train A moves with a speed of 45 m/s from
Natalija [7]

Answer:

105 m/s

Explanation:

Given that the speed of train A, V_A = 45 m/s from west to east.

Speed of train B, V_B = 60 m/s from east to west.

Train B is moving in the opposite direction with respect to the speed of train A. Assuming that the speed from east to west direction is positive.

So, the speed of train A from east to west= - 45 m/s

The speed of train B w.r.t train A = V_B - V_A=60-(-45)=60+45=105 m/s

Hence, the speed of train B w.r.t train A is 105 m/s from east to west.

5 0
3 years ago
A 1502.7 kg car is traveling at 33.1 m/s when
Bond [772]

By definition of average acceleration,

<em>a</em> = (20 m/s - 33.1 m/s) / (4.7 s) ≈ -2.78 m/s²

Vertically, the car is in equilibrium, so the net force is equal to the friction force in the direction opposite the car's motion:

∑ <em>F</em> = (1502.7 kg) (-2.78 m/s²) ≈ -4188.38 N ≈ -4200 N

If you just want the magnitude, drop the negative sign.

5 0
3 years ago
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