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amm1812
3 years ago
10

A slinky is stretched across a classroom and moved up and down at a frequency of 2 hz. if the corresponding wave velocity is 4.2

m s , determine the wavelength of the slinky wave.
Physics
1 answer:
marusya05 [52]3 years ago
4 0
Velocity of a wave is the amount of wavelength multiplied by its frequency. Moreover, derivations would be;wavelength?
Hence wavelength would be velocity divided by the frequency.Result is 2.1 mThank you for your question. Please don't hesitate to ask in Brainly your queries. 
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This property of waves is the only property where the relationship between energy and this property are indirect or inverse
yaroslaw [1]

Answer: I don't understand

Explanation:

study and pay attention

4 0
2 years ago
Calculate Vector component in Y if the hypotenuse is 32 and angle is 45
Lerok [7]

Answer:

The correct option is;

c. 22.6

Explanation:

The given parameters are;

The hypotenuse of the vector = 32

The angle of the vector = 45°

Therefore, the vector component in the y-axis is given as follows;

v_y = v \times sin(\theta)

Substituting the values from the question gives;

v_y = 32 \times sin(45^{\circ}) \approx 22.6

The vector component in the y-axis, v_y, is approximately 22.6.

8 0
2 years ago
The critical angle for a certain air-liquid surface is 47.7°. What is the index of refraction of the liquid? Round to the neares
KengaRu [80]

Answer:

The index of refraction of the liquid is 1.35.

Explanation:

It is given that,

Critical angle for a certain air-liquid surface, \theta_1=47.7^{\circ}

Let n₁ is the refractive index of liquid and n₂ is the refractive index of air, n₂ =1

Using Snell's law for air liquid interface as :

n_1\ sin\theta_1=n_2\ sin(90)

n_1\ sin(47.7)=1

n_1=\dfrac{1}{sin(47.7)}

n_1=1.35

So, the index of refraction of the liquid is 1.35. Hence, this is the required solution.

5 0
3 years ago
A 3.00 μF capacitor is charged to 480 V and a 4.00 μF capacitor is charged to 500 V . Part A These capacitors are then disconnec
pogonyaev

Q before connected = Q after connected C1V1+C2V2 = (C1+C2) V

C1= 3×10^-6 F

V1= 480v

C2= 4×10^-6 F

V2= 500v

(3×10^-6)×(480) + (4×10^-6)×(500) = (3×10^-6 + 4×10^-6) × V

Simplifying the above, we get:

( 1440× 10^-6) + (2000 ×10^-6) = (7 × 10^-6) × V.

Further simplified as:

3440 × 10^-6 = 7 × 10^-6 × V

Making V the subject

V = 491.43volts

Therefore the potential difference across each capacitor is 491.43v

4 0
3 years ago
1 What conclusion can you draw about semicircular canals from their name ? A Their shape B Their size Their location in your bod
oee [108]

Answer:

A. Their shape

Explanation:

The name clearly shows that the shape of these canals are semi-circular. The semi-circular canals consist of three tubes filled with fluid and located in the inner ear. They help to maintain balance and transmit impulses through the movement of the fluids. The impulses sent through these fluids are sent to the brain for interpretation.

The function of the canals are not indicated by the name, rather the shape is hinted through the name.

7 0
2 years ago
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