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Inga [223]
3 years ago
15

Why is using fossil fuels considered unsustainable?

Physics
2 answers:
Elena L [17]3 years ago
8 0

Answer:

Fossil Fuel is limited it is like coal there is a limit and it won't last forever. This also contributes that it is not safe for the environment as well as the safety and health of people. This is similar to when there are many factories around an area there is going to be a high percentage of respiratory diseases such as asthma.

ikadub [295]3 years ago
3 0

Answer:

Fossil fuels take millions of years to replenish

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a 70 kg desk sits on the floor motionless If gravity is pulling it with an acceleration of 9.8 m/s/s how much force is gravity e
adell [148]

Since force is mass*acceleration,

F = 70kg * 9.8 m/s

3 0
4 years ago
The resistance of a conductor is 10 ohm at 50 degree celsius and 15 ohm at 100 degree celsius. Calculate its resistance at 0 deg
hammer [34]
1500
Step back and get your help
3 0
3 years ago
What is an input force?
Readme [11.4K]

Answer:

C i believe

Explanation:

im pretty sure thats it

5 0
3 years ago
A cable with mass 0.5 kilograms per meter (kg/m) is used to lift 150 kg of coal up a mine shaft 50 meters deep. Set up the integ
zalisa [80]

Answer:

W=-\int_{0}^{50}[150-0.5y]dy

Explanation:

the integral for the work is:

W=\int\vec{F}\cdot d\vec{l}=\int(-M(y)g)dy

the work is against the gravitational force. While the coal is going up, M(y) is changing due to the length of the cable is lower. We can describe this by using the following formula

M(y)=150kg-0.5\frac{kg}{m}y

Thus , the integral for the work is:

W=-\int_{0}^{50}[150-0.5y]dy

hope this helps!!

6 0
4 years ago
The power of a lens is defined as the reciprocal of its focal length: P = 1/f. (Thus power is measured in inverse meters, called
Len [333]

Answer:

This the power of combination is given by

P_{combination}=\frac{1}{F}=\frac{d+f_{2}-f_{1}}{f_{2}(d-f_{1})}

Explanation:

Let 'F' be the focal length of the combination of the two lenses and the focal length's of individual lenses be f_{1},f_{2}

We know that focal length is the position of image when object is placed at infinity

Let us place the the object at infinity with respect to the first lens thus the position of image formed by the first lens shall be obtained using lens formula as

\frac{1}{f_{1}}=\frac{1}{u}+\frac{1}{v}

Applying values we get

\frac{1}{f_{1}}=\frac{1}{\infty }+\frac{1}{v}\\\\\Rightarrow \frac{1}{f}=0+\frac{1}{v}\\\\\therefore v=+f_{1}

Now this position of image formed by the first lens act's as object for the second lens, thus we have

\frac{1}{f_{2}}=\frac{1}{-(d-f_{1})}+\frac{1}{v}\\\\\Rightarrow \frac{1}{f_{2}}+\frac{1}{d-f_{1}}=\frac{1}{v}\\\\\therefore \frac{1}{v}=\frac{(d-f_{1})+f_{2}}{f_{2}(d-f_{1})}\\\\=\frac{1}{v}=\frac{d+f_{2}-f_{1}}{f_{2}(d-f_{1})}\\\\\therefore v_{f}=\frac{f_{2}(d-f_{1})}{d+f_{2}-f_{1}}

Since image of an object placed at infinity will be formed at v_{f}=\frac{f_{2}(d-f_{1})}{d+f_{2}-f_{1}} thus the focal length of the combination of the 2 thin lenses will be F=\frac{f_{2}(d-f_{1})}{d+f_{2}-f_{1}}

This the power of combination is given by

P_{combination}=\frac{1}{F}=\frac{d+f_{2}-f_{1}}{f_{2}(d-f_{1})}

(For the sake of question we assume lenses to be convex although the same procedure is valid for all other lenses)

5 0
4 years ago
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