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2 years ago

What are some guidelines for preventing quackery and fraud when shopping? Select

Physics

1 answer:

artcher [175]2 years ago

6 0

The steps/guidelines for preventing quackery and fraud when shopping are :

Be suspicious of a sales pitch that promises results too good to be true

Be cautious of mail-order and internet sales
Be wary of product claims
Be wary of advisors who sell products

<h3>What is Quackery and Fraud </h3><h3 />

Quackery involves the claim of knowledge and provision of a fake and dishonest service to unsuspecting customers or clients and this is very common in medicine.

Fraud is the false representation of a material or service in order to cause loss of money or pain to an unsuspecting client or customer. some steps to prevent fraud are as follows :

If a sales pitch is too good to be true one should keep off from such product/service.

when making internet sales and mail-order customers should be careful as there are a lot of imposters on the internet.

Hence we can conclude that The steps/guidelines for preventing quackery and fraud when shopping are as listed above

Learn more about Fraud : brainly.com/question/1260589

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3 years ago

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3 years ago

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3 years ago

You want to get from a point a on the straight shore of the beach to a buoy which is 60 meters out in the water from a point b o

loris [4]

The time t for a constant speed is given by:
t = distance/ velocity

Let's call the distance to run on the beach x₁ and the remaining distance to swim x₂, then the equation becomes:
$t = \frac{x_1}{5} + \frac{x_2}{3}$

The distance x₂ depends on x₁:
$x_2 = \sqrt{(70 - x_1)^2 + 60^2}$

So: $t = \frac{x_1}{5} + \frac{ \sqrt{(70 - x_1)^2 + 60^2} }{3}$

Find the minimum by setting the derivative to zero: $\frac{dt}{dx_1} = 0$
$\frac{dt}{dx_1} = \frac{1}{5} - \frac{1}{3} \frac{70 - x_1} {\sqrt{70 - x_1)^2 + 60^2} } = 0$
$70 - x_1 = \frac{3}{5} \sqrt{(70 - x_1)^2 + 60^2} \\ \\ (70 - x_1)^2 = \frac{9}{25}((70 - x_1)^2 + 60^2) \\ \\ \frac{16}{25}(70 - x_1)^2 = \frac{9}{25}60^2 \\ \\ \frac{4}{5}(70 - x_1) = \frac{3}{5}60 \\ \\ x_1 = 25$

You should stop running 70m - 25m = 45m from b.

4 0

3 years ago