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3 years ago

What are some guidelines for preventing quackery and fraud when shopping? Select

Physics

1 answer:

artcher [175]3 years ago

6 0

The steps/guidelines for preventing quackery and fraud when shopping are :

Be suspicious of a sales pitch that promises results too good to be true

Be cautious of mail-order and internet sales
Be wary of product claims
Be wary of advisors who sell products

<h3>What is Quackery and Fraud </h3><h3 />

Quackery involves the claim of knowledge and provision of a fake and dishonest service to unsuspecting customers or clients and this is very common in medicine.

Fraud is the false representation of a material or service in order to cause loss of money or pain to an unsuspecting client or customer. some steps to prevent fraud are as follows :

If a sales pitch is too good to be true one should keep off from such product/service.

when making internet sales and mail-order customers should be careful as there are a lot of imposters on the internet.

Hence we can conclude that The steps/guidelines for preventing quackery and fraud when shopping are as listed above

Learn more about Fraud : brainly.com/question/1260589

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3 years ago

What other factor affected the gravitational force between the two objects in this simulation?

neonofarm [45]

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A pendulum is made up of a metal cylinder of diameter d attached to a thin string. The pendulum passes through a photogate at th

ankoles [38]

The calculated total mechanical energy will reduce if the oscillation is not perpendicular to the photogate.

<h3>Mechanical energy at the lowest position of the pendulum</h3>

The mechanical energy at the lowest position of the pendulum is calculated as follows;

$U = K.E = \frac{1}{2}mv^2$

<h3>When the direction of the motion changes</h3>

let the velocity of the pendulum = vsin(θ)

when the velocity is perpendicular = vsin(90) = v

At any direction different from perpendicular direction, the mechanical energy reduces by;

$\Delta U = \frac{1}{2} mv^2 - \frac{1}{2} m(vsin\theta)^2\\\\\Delta U = \frac{1}{2} m(v^2 - v^2sin^2\theta)\\\\\Delta U = \frac{1}{2} mv^2(1 - sin^2\theta )$

Thus, the calculated total mechanical energy will reduce if the oscillation is not perpendicular to the photogate.

Learn more about mechanical energy here: brainly.com/question/24443465

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3 years ago

An astronaut weighs 199 lb. what is his weight in newtons?

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1 lb = 4.45 Newtons (rounded)

199 lbs = approx 885 Newtons

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3 years ago

Please help me on number 9 :)

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The answer is a !!!!!!

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