Answer:
(a)T= M2 × g, (b)T= (M1 + M2)g, (c)T= M2 (a + g) and (d)T=(M1 + M2) (a + g)
Explanation:
M1 is hanged upper and M2 is lower at Rest.
(a) For M2
T2 = Weight of the Body M2= M2 × g
(b) T1 = Weight of the Body M2 + Weight of the Body M2
T1 = M1 g + M2 g = (M1 + M2)g
M1 is hanged upper and M2 is lower at accelerated upwards ( F = T - W)
(c) For M2
⇒T = M2a + M2g = M2 (a + g)
(d) For M1
T = (M1 + M2) a + (M1 + M2) g
⇒ T = (M1 + M2) (a + g)
Answer:
0.09 m/s to the right
Explanation:
The principle of conservation of linear momentum states that in a system of colliding objects, the total momentum before collision is equal to the total momentum after collision, provided there is no external force.
The total momentum, in this question, is the sum of the momentum of the the two marbles. We assume velocity to the right is positive while to the left is negative. Thus, total initial momentum is
After collision, the first marble goes left. Let the velocity of the other marble be v. Then we have
Equating both momenta,
Hence, the larger goes right with a velocity of 0.09 m/s (since it has a positive sign).