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liberstina [14]
3 years ago
14

Cells are differentiated when

Chemistry
1 answer:
Serjik [45]3 years ago
4 0

Answer:

D I think.............

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What reagent is used to test for the presence of indole?
lubasha [3.4K]
The indole test is a qualitative procedure for determining the ability of bacteria to produce indole by deamination of tryptophan. Using Kovacs tube method, indole combines, in the presence of a tryptophan rich medium, with p-Dimethylaminobenzaldehyde at an acid pH in alcohol to produce a red-violet compound.
7 0
3 years ago
How many atoms are in 19.6 g of Sodium?
Hitman42 [59]

Answer:

Number of atoms = 5.1345 x 10²³

Explanation:

Given:

Mass of sodium = 19.6

Find:

Number of atoms

Computation:

We know that atomic mass of sodium is 22.98

So,

Number of atoms = [Mass of sodium/atomic mass of sodium]Avogadro's number

Number of atoms = [19.6 / 22.98]6.02 x 10²³

Number of atoms = 5.1345 x 10²³

can i have Brainliest i need 1 more

7 0
3 years ago
What is the number of carbon atoms in the ring portion of the haworth structure of glucose?
Anna35 [415]
I have attached the picture ot the H<span>aworth structure of glucose.

You can count in total 6 carbon atoms but only 5 are in the ring portion of the structure.

Therefore, the answer is 5.
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8 0
3 years ago
Calculate the number of moles of solute in 27.55 mL of 0.1185 M K2Cr2O7(aq).
Zinaida [17]

Answer:

0.01185M = moles/0.02755L

0.02755*0.01185=0.00032647

Explanation:

7 0
3 years ago
How many electrons would be transferred in either a voltaic or electrolytic cell that uses the following half reactions
omeli [17]

Answer:

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

Explanation:

Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V

Mg^{2+}(aq) + 2 e^- \rightarrow Mg (s),E^o = -2.37 V

The substance having highest positive reduction E^o potential will always get reduced and will undergo reduction reaction.

Reduction : cathode

Fe^{3+} (aq) + 3 e^-\rightarrow Fe (s) ,E^o = -0.036 V..[1]

Oxidation: anode

Mg(s)\rightarrow Mg^{2+}(aq) + 2 e^-,E^o = 2.37 V..[2]

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

E^o_{cell}=-0.036V-(-2.37 V)=2.334 V

The overall reaction will be:

2 × [1] + 3 × [2] :

2Fe^{3+} (aq) + 3Mg(s)+6e^-\rightarrow 2Fe (s)+3Mg^{2+}(aq)+6e^-

Electrons on both sides will get cancelled :

2Fe^{3+} (aq) + 3Mg(s)\rightarrow 2Fe (s)+3Mg^{2+}(aq)

Numbers of electrons transferred in the electrolytic or voltaic cell is 6 electrons.

5 0
3 years ago
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