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liberstina [14]
3 years ago
14

Cells are differentiated when

Chemistry
1 answer:
Serjik [45]3 years ago
4 0

Answer:

D I think.............

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Every cell has a nucleus unless it is RNA which is involved with DNA movement
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3 years ago
Determine the nuclear composition (number of protons and neutrons) of the following isotopes. (a) chromium-52 protons neutrons (
madreJ [45]

Answer: a) chromium-52 :  protons = 24, neutrons = 28

selenium - 80 :  protons = 34, neutrons = 46

molybdenum-98:  protons = 42, neutrons = 56

xenon-132:  protons = 54, neutrons = 78

ytterbium-174 :  protons = 70, neutrons = 104

Explanation:

Atomic number : It is defined as the number of electrons or number of protons present in a neutral atom.

Thus, number of protons = atomic number

Mass number is the number of the entities present in the nucleus which is the equal to the sum of the number of protons and electrons.

Mass number = Number of protons + Number of neutrons

a) chromium-52 :

Atomic number of Chromium is 24 hence number of protons  = 24

52= 24+ Number of neutrons

Number of neutrons = 28

b) selenium - 80 :

Atomic number of selenium is 34 hence number of protons  = 34

80 =  34 +  Number of neutrons

Number of neutrons = 46

c) molybdenum - 98 :

Atomic number of molybdenum is 42 is  hence number of protons  = 42

98 =  42 +  Number of neutrons

Number of neutrons = 56

d) xenon-132:

Atomic number of xenon is 54 hence number of protons  = 54

132 =  54 +  Number of neutrons

Number of neutrons = 78

e) ytterbium-174:

Atomic number of ytterbium is 70 and  hence number of protons  = 70

174 = 70 +  Number of neutrons

Number of neutrons = 104

6 0
3 years ago
If a 58 g sample of metal at 100 c is placed into calorimeter containing 60g of water at 18 c , the temperature of the water inc
tatiyna

Answer:

The water will absorb 1004.16 Joule of heat

Explanation:

Step 1: Data given

Mass of the metal = 58.00 grams

Temperature of the metal = 100.00 °C

Mass of water = 60.00 grams

Temperature of water = 18.00 °C

Final temperature = 22.00 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate the amount of heat absorbed by the water in joules

Q = mass *specific heat *ΔT

 ⇒ with Q = the heat absorbed by water

⇒ with mass of water = 60.00 grams

⇒ with specific heat of water = 4.184 J/g°C

⇒ with ΔT = The change in temperature of water = T2 - T1 = 22 - 18 = 4.0 °C

Q = 60.00 * 4.184 J/g°C * 4.0 °C

Q = 1004.16 J

The water will absorb 1004.16 Joule of heat

6 0
3 years ago
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