At it's maximum height the acceleration is still 9.8m/s. On the earths surface, all objects are constantly under acceleration due to gravity. It is perculiar, but true. Under acceleration, only the velocity changes (as a general rule).
Answer:
a. speed, v = 0.97 c
b. time, t' = 20.56 years
Given:
t' = 5 years
distance of the planet from the earth, d = 10 light years = 10 c
Solution:
(a) Distance travelled in a round trip, d' = 2d = 20 c = L'
Now, using Length contraction formula of relativity theory:
(1)
time taken = 5 years
We know that :
time =
5 = (2)
Dividing eqn (1) by v on both the sides and substituting eqn (2) in eqn (1):
Squaring both the sides and Solving above eqution, we get:
v = 0.97 c
(b) Time observed from Earth:
Using time dilation:
Solving the above eqn:
t'' = 20.56 years
Answer:C
Explanation:
Given
Four masses are attached to the wire such that distance between two mass is L
therefore the Length of wire is 4 L
and the center of mass is at 2L
moment of inertia is distribution of mass from its rotational axis
thus moment of Inertia I is given by
Complete Question
A 0.025-kg block on a horizontal frictionless surface is attached to an ideal massless spring whose spring constant is 150 N/m. The block is pulled from its equilibrium position at x = 0.00 m to a displacement x = +0.080 m and is released from rest. The block then executes simple harmonic motion along the horizontal x-axis. When the displacement is x = 0.024 m, what is the kinetic energy of the block?
Answer:
The kinetic energy is
Explanation:
From the question we are told that
The mass of the block is
The spring constant is
The length of first displacement is
The length of first displacement is
At the the kinetic energy is mathematically evaluated as
Where is the change in energy stored on the spring which is mathematically represented as
=>
Substituting value
Answer:
<h2> 27m/s</h2>
Explanation:
Given data
initital velocity u=15m/s
deceleration a=3m/s^2
time t= 4 seconds
final velocity v= ?
Applying the expression
v=u+at------1
substituting our data into the expression we have
v=15+3*4
v=15+12
v=27m/s
The velocity after 4 seconds is 27m/s