Answer:
T= 257.36 k
Explanation:
using the ideal gas law
pv=nRt
first, convert pressure from mmhg to kpa
312 x (101.3\760)= 41.58 kpa
R is constant= 8.31
to get n(number of moles)
n=m\M (m is mass, M is molar mass)
molar mass of argon is 39.948
n= 2.33\39.948
n=0.0583
substitute;
41.58 x 3 = 0.0583 x 8.31 x T
T= (41.58 x 3)\ (0.0583 x 8.31)
T= 257.36 k
The molecular formula:
![N_x(O_2)_x](https://tex.z-dn.net/?f=N_x%28O_2%29_x)
![M_{N_x(O_2)_x}=x \times M_N + x \times 2 \times M_O \\ \\ m_N=14 \ \frac{g}{mol} \\ m_O=16 \ \frac{g}{mol} \\ M_{N_x(O_2)_x}=92 \ \frac{g}{mol} \\ \\ 92=x \times 14+x \times 2 \times 16 \\ 92=14x+32x \\ 92=46x \\ \frac{92}{46}=x \\ x=2 \\ \\ N_2(O_2)_2 \Rightarrow N_2O_4](https://tex.z-dn.net/?f=M_%7BN_x%28O_2%29_x%7D%3Dx%20%5Ctimes%20M_N%20%2B%20x%20%5Ctimes%202%20%5Ctimes%20M_O%20%5C%5C%20%5C%5C%0Am_N%3D14%20%5C%20%5Cfrac%7Bg%7D%7Bmol%7D%20%5C%5C%0Am_O%3D16%20%5C%20%5Cfrac%7Bg%7D%7Bmol%7D%20%5C%5C%20M_%7BN_x%28O_2%29_x%7D%3D92%20%5C%20%5Cfrac%7Bg%7D%7Bmol%7D%20%5C%5C%20%5C%5C%0A92%3Dx%20%5Ctimes%2014%2Bx%20%5Ctimes%202%20%5Ctimes%2016%20%5C%5C%0A92%3D14x%2B32x%20%5C%5C%0A92%3D46x%20%5C%5C%0A%5Cfrac%7B92%7D%7B46%7D%3Dx%20%5C%5C%0Ax%3D2%20%5C%5C%20%5C%5C%0AN_2%28O_2%29_2%20%5CRightarrow%20N_2O_4)
The molecular formula is N₂O₄.
The answer is a. concentrated. (If the statement was instead that large amounts of water was involved and smaller amounts of salt, the answer would be instead c. dilute)
4.1 is acidic on the Ph scale