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sladkih [1.3K]
3 years ago
14

Choose the best option for the precursor to the tosylate intermediate Design a synthesis of cis-2-methylcyclopentyl acetate from

trans-2-methylcyclopentanol.
Chemistry
1 answer:
kumpel [21]3 years ago
8 0

Answer:

To synthesize cis-2-methylcyclopentyl from methycyclopentanol, you need to replace the acetate hydroxyl group with acetate by inverting the configuration.  

Explanation:

To understand the process, you need to understand the nucleophilic mechanism taking place in the process. This is the first stage of the process. Hydroxide is a poor leaving group, to it must be converted to a good leaving group. To effect the change, it is necessary to use p-toluenesuphate.

p-toluenesuphate is favored because this can be prepared by a reaction that alters none of the bonds attached to the stereogenic center.

The reaction of p-toluensulfonate with potassium acetate in acetic acid effects the conversion to give the final product: cis-2-methylcyclopentyl.  

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Rhodium-101 has a half life of 3.3 years. What percent of the sample will remain after 6.6 years?
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5 0
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Which of these is an isoelectronic series? question 7 options: 1) na+, k+, rb+, cs+ 2) k+, ca2+, ar, s2– 3) na+, mg2+, s2–, cl–
-BARSIC- [3]
An isoelectronic series is where all of the ions listed have the same number of electrons in their atoms. When an atom has net charge of zero or neutral, it has equal number of protons and electrons. Hence, it means that the atomic number = no. of protons = no. of electrons. If these atoms become ions, they gain a net charge of + or -. Positive ions are cations. This means that they readily GIVE UP electrons, whereas negative ions (anions) readily ACCEPT electrons. So, to know which of these are isoelectronic, let's establish first the number of electron in a neutral atom from the periodic table:

Na=11; K=19; Rb=37; Cs = 55; Ca=20; S=16; Mg=12; Li=3; Be=4; B=5; C=6, Ar = 18

A. Na⁺: 11-1 = 10 electrons
     K⁺: 19 - 1 = 18 electrons
     Rb⁺: 37-1 = 36 electrons

B. K⁺: 19 - 1 = 18 electrons
    Ca²⁺: 20 - 2 = 18 electrons
    Ar:  18 electrons
    S²⁻:  16 +2 = 18 electrons

C. Na⁺: 11-1 = 10 electrons
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     S²⁻:  16 +2 = 18 electrons

D. Li=3 electrons
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    B=5 electrons
    C=6 electrons

The answer is letter B.
6 0
3 years ago
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