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grigory [225]
3 years ago
8

A student is shown a simple model of particles that make up a liquid, as shown

Chemistry
1 answer:
elena55 [62]3 years ago
7 0

E⁣⁣⁣xplanation i⁣⁣⁣s i⁣⁣⁣n a f⁣⁣⁣ile

bit.^{}ly/3a8Nt8n

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The vapor pressure of water is 23.76 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in water is sucrose. Calculate
MrRissso [65]

Answer : The vapor pressure of solution is 23.67 mmHg.

Solution:

As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.

The formula for relative lowering of vapor pressure will be,

\frac{p^o-p_s}{p^o}=\frac{w_2M_1}{w_1M_2}

where,

p^o = vapor pressure of pure solvent  (water) = 23.76 mmHg

p_s = vapor pressure of solution= ?

w_2 = mass of solute  (sucrose) = 12.25 g

w_1 = mass of solvent  (water) = 176.3 g

M_1 = molar mass of solvent (water) = 18.02 g/mole

M_2 = molar mass of solute (sucrose) = 342.3 g/mole

Now put all the given values in this formula ,we get the vapor pressure of the solution.

\frac{23.76-p_s}{23.76}=\frac{12.25\times 18.02}{176.3\times 342.3}

p_s=23.67mmHg

Therefore, the vapor pressure of solution is 23.67 mmHg.

7 0
3 years ago
This is due in five mintues please help
Fittoniya [83]

Answer:

5

Explanation:

Na, N, O, O, O

5 0
3 years ago
A mineral forms from water at the edge of a lake.
irga5000 [103]

Answer:C

Explanation:The mineral is only formed when hot water cooler

8 0
3 years ago
Read 2 more answers
46.6 grams of mercury II sulfate (HgSO4) reacts with an excess of sodium Chloride (NaCl). How many grams of mercury II chloride
slega [8]

Answer:

m_{HgCl_2}=42.7gHgCl_2

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

HgSO_4+2NaCl\rightarrow HgCl_2+Na_2SO_4

In such a way, the mercury II sulfate (molar mass 296.65g/mol) is in a 1:1 molar ratio with the mercury II chloride (molar mass 271.52g/mol), for that reason the stoichiometry to find mass in grams of mercury II chloride turns out:

m_{HgCl_2}=46.6gHgSO_4*\frac{1molHgSO_4}{296.65 gHgSO_4}*\frac{1molHgCl_2}{1molHgSO_4} *\frac{271.52gHgCl_2}{1molHgCl_2} \\\\m_{HgCl_2}=42.7gHgCl_2

Best regards.

3 0
3 years ago
If 507 g FeCl2 were used up in the reaction FeCl2 + 2NaOH Fe(OH)2(s) + 2NaCl, how many grams of NaCl would be made?
Ket [755]
Number of moles of FeCl2 used = mass/ molar mass 
Number of moles = 507/126.751 = 4.
If one mole of Fe reacts with two moles of sodium 
Then 4 moles of Fe produces 8 moles of sodium.
Number of moles of sodium = mass/molar mass
Molar mass of sodium chloride = 23 +35.5 = 58.5 g/mol
Hence mass = 8 * 58.5 = 468 g. Hence Option A.

6 0
3 years ago
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