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Andrei [34K]
2 years ago
11

A laser source has a bandwidth of 30GHz (a) Calculate the coherence length of the source b) What is the time separation of secti

ons of the light wave that can still interfere? source, can have?
Physics
1 answer:
abruzzese [7]2 years ago
6 0

Explanation:

It is given that,

Bandwidth of a laser source, f=30\ GHz=30\times 10^9\ Hz

(b) Let t is the time separation of sections of sections of the light wave that can still interfere. The time period is given by :

T=\dfrac{1}{f}

T=\dfrac{1}{30\times 10^9}

T=3.33\times 10^{-11}\ s

(a) Let h is the coherence length of the source. It is given by :

l=c\times T

c is the speed of light

l=3\times 10^8\times 3.33\times 10^{-11}

l = 0.0099 m

Hence, this is the required solution.

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A cabinet weighing 100 N is placed on a floor. The amount of contact area between the cabinet and the floor is 0.5 m2. How much
katovenus [111]

Answer:

p = 200Pa

Explanation:

From its definition, the pressure depends on the force exerted on the floor by the cabinet, and the perpendicular area in which it is applied. This is expressed in the formula:

p=\frac{F}{A}

Since the force the cabinet exerts on the floor is its weight, we can use the given values to calculate the pressure exerted on the floor:

p=\frac{100N}{0.5m^{2} } =200Pa

In words, the pressure the cabinet exerts on the floor is 200Pa.

4 0
2 years ago
The weight of a body above sea level varies inversely with the square of the distance from the center of Earth. If a woman weigh
Serjik [45]

Answer:

89.16pounds

Explanation:

The equation that defines this problem is as follows

W=k/X^2

where

W=Weight

K= proportionality constant

X=distance from the center of Earth

first we must find the constant of proportionality, with the first part of the problem

k=WX^2=131x3960^2=2054289600pounds x miles^2

then we use the equation to calculate the woman's weight with the new distance

W=2054289600/(4800)^2=89.16pounds

4 0
3 years ago
Please answer with an explanation.
nydimaria [60]

Answer:

A, D, E

Explanation:

The force of Earth's gravitational pull is equal to the mass of the object times the acceleration due to gravity:

W = mg

The greater the mass, the greater the pull.  A truck, bicycle, and camel all have greater mass than a baseball.

3 0
3 years ago
How do oxygen and beryllium atoms transform into oxygen ion O2- and Be2 beryllium ion Be2? tysm
Hoochie [10]
On the whole, the metals burn in oxygen to form a simple metal oxide. Beryllium is reluctant to burn unless it is in the form of dust or powder. Beryllium has a very strong (but very thin) layer of beryllium oxide on its surface, and this prevents any new oxygen getting at the underlying beryllium to react with it.
7 0
2 years ago
Read 2 more answers
A solid 0.4550 kg ball rolls without slipping down a track toward a vertical loop of radius R = 0.6750 m . What minimum translat
Talja [164]

Answer:

u = 3.35 m/s

Explanation:

given,

mass , m = 0.455 kg  

R = 0.675 m

Height of Loop = 1.021 m

the speed required at the top of loop be v

equating the force vertically

m g =\dfrac{mv^2}{r}

9.81 =\dfrac{v^2}{0.675}

v² = 6.622

v = 2.57 m/s

Let the initial speed of ball be u

using conservation of energy

\dfrac{1}{2}mu^2 + \dfrac{1}{2}I\omega^2 + m g h = \dfrac{1}{2}I\omega^2 + \dfrac{1}{2}mv^2+ m g (2 R)

where, I =\dfrac{2}{5}mr^2

\dfrac{1}{2}mu^2 + \dfrac{1}{2}(\dfrac{2}{5}mr^2)(\dfrac{u}{r})^2 + m g h = \dfrac{1}{2}(\dfrac{2}{5}mr^2)(\dfrac{v}{r})^2 + \dfrac{1}{2}mv^2+ m g (2 R)

0.7 u^2 + g H = 0.7 v^2 + g(2R)

0.7 u^2 +9.81 \times 1.021= 0.7\times 2.57^2 + 9.81 \times 2\times 0.675)

0.7 u² = 7.85092

u² = 11.2156

u = 3.35 m/s

the initial  speed is 3.35 m/s

8 0
2 years ago
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