T: 8x+19
7x-2(4-2x)+6(5-x)-x+2-(6x+5) = 7x-8+2x+30+6x-x+2-6x-5 = 8x+19
Y: 56-8x
9-(-2-3x)+4(-x+6)-x+12-3(2x-3) = 9+2+3x-4x+24-x+12-6x+9 = 56-8x
The value that would make the ratios equal to 4 to 10... I believe it would be 2 to 5
Answer:
a) PR = 17 cm, b) QR = 6 cm
Step-by-step explanation:
∠Q=90, so PQ and QR are legs, and PR is hypotenuse.
Pythagorean theorem PQ² + QR² = PR²
a) PQ² + QR² = PR²
8² + 15² = PR²
PR² = 289
PR = 17 cm
b) PQ² + QR² = PR²
8² + QR² = 10²
64 + QR² = 100
QR² = 36
QR = 6 cm