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sesenic [268]
3 years ago
13

What is 31/32 as a decimal?

Mathematics
2 answers:
ohaa [14]3 years ago
8 0
.96875. All you have to do is divide the top number by the bottom number to what the answer is.
Westkost [7]3 years ago
6 0
Divide the top and bottom together
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Here is a list of ages (years) of children in a room: 5, 8, 5, 6, 8, 3, 6 State the median.
Ierofanga [76]

Answer:

6

Step-by-step explanation:

The median of a list of numbers is the number found in the "middle" of all the numbers. What this means is that it has the same amount of numbers larger and smaller than it in the list. To find the median, we first have to organize the list from least to greatest. Doing this, we get 3, 5, 5, 6, 6, 8, 8.

Now that we have the list, we can find the "middle number" by taking off numbers the highest number then the lowest number. Doing this we get

3, 5, 5, 6, 6, 8, 8

5, 5, 6, 6, 8

5, 6, 6

6

This means our median is 6.

7 0
3 years ago
Read 2 more answers
The poster shows how many of its games of football team has won so far.Express this information as a fraction a,percent and as a
Harrizon [31]
12/15
Divide 12 by 15 and then you should get 0.8
0.8 is obviously equal to 8/10ths or 80% 
Hope this helps :)
4 0
3 years ago
Find dy of the fol<br>of the following<br>fuction​
ikadub [295]

write question properly bro

8 0
3 years ago
The cost of admission for a student is $4 less than the cost of admission for an adult.
mash [69]
A. x-4; x representing the cost of admission for adults.
b. $3.50
c. $6
7 0
4 years ago
Read 2 more answers
The average (arithmetic mean) of y numbers is x. If 30 is added to the set of numbers, then the average will be x − 5. What is t
Alenkasestr [34]

Answer:

y = \frac{1}{5}(x^{2}-35x)

Step-by-step explanation:

Let the total numbers are n.

If the average of y numbers is x then we can form an equation

\frac{y}{n}=x

⇒ \frac{n}{y}=\frac{1}{x}

⇒ n = \frac{y}{x} --------(1)

Now 30 is added to the set of numbers then average becomes (x - 5)

\frac{y+30}{n+1}=(x-5)

⇒ \frac{(n+1)}{(y+30)}=\frac{1}{(x-5)}

⇒ (n + 1) = \frac{y+30}{x-5}

⇒ n = \frac{y+30}{x-5} - 1 ----- (2)

Now we equate the values of n from equation 1 and 2

\frac{y}{x} = \frac{y+30}{x-5} - 1

y(x - 5) = x(y + 30) - x(x - 5)  [ By cross multiplication ]

xy - 5y = xy + 30x - x² + 5x

xy - xy - 5y = 35x - x²

-5y = 35x - x²

x² - 35x = 5y

y = \frac{1}{5}(x^{2}-35x)

6 0
3 years ago
Read 2 more answers
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