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sineoko [7]
4 years ago
8

A small squishy ball is thrown against the side of a large cube of concrete. While the objects are in contact with each other, w

hich experiences the larger force?
Physics
1 answer:
Amanda [17]4 years ago
4 0

Answer: The squishy ball

Explanation:

The squishy ball experiences a larger force due to its soft nature. The force of the squishy ball cannot overcome the concrete cube due to the weight of the concrete and as such the weight of the concrete cube will overcome the force exerted on it by the squishy ball making the ball to experience much larger force.

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Answer: P = 40 W

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Work is the product of force and distance so W = Fd.

So the working equation will be:

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Is the amount of power exerted.

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Answer:

a)  V=7.5m/s

b) rms=8.4m/s

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Explanation:

From the question we are told that:

Sample size N=15

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b)

Generally the equation for RMS speed of the particle is mathematically given by

  rms=\sqrt{\frac{\sum(nv^2)}{N}}

  rms=\sqrt{\frac{2^2+2(3)^2+3(5)^2+4(8)^2+3(9)^2+2(15)^2}{15}}

  rms=\sqrt{69.73}

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c

Generally the most probable speed is 8m/s as it the most posses by particles being the average

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