A ___ is one way a star might die and it can trigger the beginning of a new stars life cycle .

Groups of students are making measurements of small cars rolling across a table. the class has measuring tapes with markings in

TiliK225 [7]

To find the accurate measurement of small cars, the teacher asks students to make all the measurements in centimeters.

Centimeters Measurements:

A centimeter is a metric unit of measurement used for measuring the length of an object, It is written as cm
Centimeter is one hundredth of a meter, 1 meter is 0.01 cm.

Inches measurements:

An inch can be defined as a unit of length in the customary system of measurement. Length in inches is either represented by in or ''.
1 meter is equal to 39.37 inches

here, the cars are small objects.

The number of centimeters is always bigger,

because a centimeter unit is smaller than an inch unit, and it takes more of them when we are measuring.

Hence,

To find the accurate measurement of small cars, the teacher asks students to make all the measurements in centimeters.

Learn more about accurate measurement here:

<u>brainly.com/question/4119127</u>

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4 0

2 years ago

A small mailbag is released from a helicopter that is descending steadily at 1.20 m/s. (a) After 5.00 s, what is the speed of th

gladu [14]

Answer:

50.2m/s

Explanation:

Using first equation of motion we have

V= u+gt

V= final speed

U= initial speed

So v = 1.2m/s + 9.8(5s)

50.2m/s

3 0

3 years ago

8. Two positive charges (+8.0 mC and +2.0 mC) are separated by 300 m. A third charge is placed at distance r from the +8.0 mC ch

muminat

Answer:

0.20 km

Explanation:

The computation of the distance r is shown below:

This can be calculated by using the following formula

As we know that

$\frac{k_q_1}{r^2} = \frac{k_q_1}{(300 - r)^2}$

where,

q_1 is 8 mC

q_2 is 2 mC

Now placing these values

Now

$\frac{k (8 \times 10^{-3c})}{r^2} = \frac{k (2 \times 10^{-3c})}{(300 - r)^2}$

$\frac{m}{r^2} = \frac{1}{(300 - r)^2}$

$\frac{2}{r} = \frac{1}{300 - r}$

r = 600 - 2r

r = 200 m

r = 0.20 km

We simply applied the above formula to determine the distance of r

Hence, the distance r is 0.20 km

4 0

3 years ago

A river flows at a speed vr = 5.88 km/hr with respect to the shoreline. A boat needs to go perpendicular to the shoreline to rea

Elodia [21]

Answer:

is is a

Explanation:

4 0

3 years ago

A steel ball is whirled on the end of a chain in a horizontal circle of radius R with a constant period T. If the radius of the

CaHeK987 [17]

Answer:

<em>The centripetal acceleration will be increased to 1.33 of its initial state. </em>

Explanation:

<h3>Centripetal acceleration</h3>

The Centripetal acceleration of an object is the acceleration of the object along a circular path moving towards the center of the circular path. The centripetal acceleration is represented in the equation bellow

$a_{c} = \frac{V^{2} }{r}$ ...................................... 1

where $a_{c}$ is the centripetal acceleration

v is the tangential velocity

and r is the radius.

<h3>How the Change of Radius Affects the Centripetal Acceleration</h3>

Reference to equation 1 the centripetal acceleration ( $a_{c}$ ) is inversely proportional ( $y = \frac{k}{x}$ ) to the radius of the circle or path. this means that when the radius increases the centripetal acceleration reduces and when the radius reduces the centripetal acceleration increases. The radius was reduced to 0.75R in the question that will amount to 1.33 $a_{c}$ increase in the centripetal acceleration. This can be obtained by multiplying the centripetal acceleration by the inverse of 0.75 which is 1.33.

Therefore, when the radius is reduced by 0.75R , the centripetal acceleration of the steel ball will increase by 1.33 $a_{c}$ . since the period is kept constant

4 0

4 years ago