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kondor19780726 [428]
3 years ago
13

Two forces (4n and 3n) pull to the left while a 12n force pulls to the right. What is the net force?

Physics
2 answers:
sineoko [7]3 years ago
5 0
Call the positive direction the one that points to the right.

                   negative force <===      ===> positive force

Then the forces are +12n, -4n, and -3n.

The net force is their sum:  (+12n - 4n - 3n) = +5 n  .

                                             (5 newtons, pointing to the right) .
Ahat [919]3 years ago
3 0
6 i believe because it makes sense too me


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Answer:

B) 20N.s is the correct answer

Explanation:

The formula for the impulse is given as:

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Impulse = mass × change in speed

Impulse = m × ΔV

Given:

initial speed  = 40m/s

Final speed = -60 m/s (Since the the ball will now move in the opposite direction after hitting the bat, the speed is negative)

mass = 0.20 kg

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Impulse = 0.20 × (40m/s - (-60)m/s)

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Which of the following is most closely related to an activated complex?
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A vertical cylindrical tank 10 ft in diameter, has an inflow line of 0.3 ft inside diameter and an outflow line of 0.4 ft inside
neonofarm [45]

Answer:

\frac{dh}{dt} = 1.3 \times 10^{-3} \frac{ft}{s}, level is rising.

Explanation:

Since liquid water is a incompresible fluid, density can be eliminated of the equation of Mass Conservation, which is simplified as follows:

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\frac{\pi}{4}\cdot D_{in}^2 \cdot v_{in}-\frac{\pi}{4}\cdot D_{out}^2 \cdot v_{out}= \frac{\pi}{4}\cdot D_{tank}^{2} \cdot \frac{dh}{dt} \\D_{in}^2 \cdot v_{in} - D_{out}^2 \cdot v_{out} = D_{tank}^{2} \cdot \frac{dh}{dt} \\\frac{dh}{dt}  = \frac{D_{in}^2 \cdot v_{in} - D_{out}^2 \cdot v_{out}}{D_{tank}^{2}}

By replacing all known variables:

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The positive sign of the rate of change of the tank level indicates a rising behaviour.

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