There are many systems of equation that will satisfy the requirement for Part A.
an example is y≤(1/4)x-3 and y≥(-1/2)x-6
y≥(-1/2)x-6 goes through the point (0,-6) and (-2, -5), the shaded area is above the line. all the points fall in the shaded area, but
y≤(1/4)x-3 goes through the points (0,-3) and (4,-2), the shaded area is below the line, only A and E are in the shaded area.
only A and E satisfy both inequality, in the overlapping shaded area.
Part B. to verify, put the coordinates of A (-3,-4) and E(5,-4) in both inequalities to see if they will make the inequalities true.
for y≤(1/4)x-3: -4≤(1/4)(-3)-3
-4≤-3&3/4 This is valid.
For y≥(-1/2)x-6: -4≥(-1/2)(-3)-6
-4≥-4&1/3 this is valid as well. So Yes, A satisfies both inequalities.
Do the same for point E (5,-4)
Part C: the line y<-2x+4 is a dotted line going through (0,4) and (-2,0)
the shaded area is below the line
farms A, B, and D are in this shaded area.
Answer:
-11/8
Step-by-step explanation:
-7/8 - 1/2 = -11/8
Answer:
(n-2)180 (this is the equation to find the sum of interior angles)
(4-2) 180 (plug in the amount of angles in the polygon and then solve)
2* 180
360
360 - 115 -100- 73= 72 (360 is the sum of all angles for this polygon. so subtract the known angles to find the unknown one)
measure of angle B is 72 degrees
Step-by-step explanation:
Answer:
The factors of the given equation are:
Step-by-step explanation:
We have :
Using middle term splitting theorem to factorize the expression :
The factors of the given equation are:
