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GREYUIT [131]
3 years ago
7

What is the benefit of using the metric system and SI Units? Question 1 options: to measure accurately on equipment to convey in

formation accurately so scientists can refer to the same quantity no matter the location or language so that all measurement systems can be used together there is no need to use the same system of measurements around the world
Physics
1 answer:
Kryger [21]3 years ago
4 0

Answer:

The correct option is;

To convey information accurately so scientists can refer to the same quantity no matter the location o language

Explanation:

The International System of Units or SI Units which was established in 1960, consist of the modernized  metric system of units.

The metric system of units came about by the signing of the Metre Convention in 1875 to initiate international cooperation in metrology which initially consisted only of the standards for the measurement of length in metre and the measurement of mass in kilograms. The units for electric currents and other physical units where included in 1875

The SI unit which is founded and also maintained by the General Conference on Weights and Measures (CGPM) is officially recognized by most countries in the world.

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BRAINLEST FOR CORRECT ANSWER PLEASE
Nata [24]

Answer:

Sledgehammer A has more momentum

Explanation:

Given:

Mass of Sledgehammer A = 3 Kg

Swing speed = 1.5 m/s

Mass of Sledgehammer B = 4 Kg

Swing speed = 0.9 m/s

Find:

More momentum

Computation:

Momentum = mv

Momentum sledgehammer A = 3 x 1.5

Momentum sledgehammer A = 4.5 kg⋅m/s

Momentum sledgehammer B = 4 x 0.9

Momentum sledgehammer B = 3.6 kg⋅m/s

Sledgehammer A has more momentum

5 0
2 years ago
Classify each process according to whether it does or does not produce a new substance.
AlexFokin [52]

The processes under chemical change are: cooking an egg, fireworks exploding, and rusting of a metal tool.

The processes under physical change are: melting ice, evaporating puddle of water, and dissolving of salt in water.

Given:

The following process:

  1. cooking an egg
  2. melting ice
  3. fireworks exploding
  4. evaporating puddle of water
  5. rusting of a metal tool
  6. Dissolving of salt in water

To find:

The classify the processes in whether it does or does not produce a new substance.

Solution:

  • Chemical change is the change when a new substance is formed due to a change in the chemical composition of the substance.
  • Physical change is the change in which no change in chemical composition takes place and the identity of the substance remains the same.
  • Cooking an egg

Chemical change, due to change in atomic arrangement egg get solidified on cooking, a new substance is formed.

  • Melting ice

Physical change, change in the state of matter is taking from solid to liquid, no new substance is formed.

  • Firework exploding

Chemical change. formation of carbon dioxide gas and sound energy, anew substance formed

  • Evaporating puddle of water

Physical change, change in the state of matter is taking from liquid to gas, no new substance is formed.

  • Rusting of metal tool

Chemical change, formation of oxides on the surface of the metal tool due to reaction between air and metal, a new substance is formed.

  • Dissolving of salt in water

Physical change, ions of salt in the solid state are changing into aqueous ions with no formation of new substance, no new substance is formed.

The processes under chemical change are: cooking an egg, fireworks exploding, and rusting of a metal tool.

The processes under physical change are: melting ice, evaporating puddle of water, and dissolving of salt in water.

Learn more about physical change and chemical change here:

brainly.com/question/864557?referrer=searchResults

brainly.com/question/13316655?referrer=searchResults

7 0
3 years ago
The deliberate radiation of electromagnetic (EM) energy to degrade or neutralize the radio frequency long-haul supervisory contr
inysia [295]

Answer:

Best explains Jamming

Explanation:

<em>The deliberate radiation of electromagnetic (EM) energy to degrade or neutralize the radio frequency long-haul supervisory control and data acquisition (SCADA) communications links, best explains what?</em>

Jamming is defined as the blocking or interference with authorized wireless communications. it's a problem  in personal area network wireless technologies. Jamming can occur inadvertently due to high levels of noise .

Jammers can send radio signals to interfere or disrupt communication flows by by decreasing the signal-to-noise ratio.They use radio frequency to interfere with communications by keeping it busy.

6 0
2 years ago
I WILL MARK BRAINLIEST!!ASAP!!! Wet Lab - Coulomb's Law lab from edge!!
anyanavicka [17]

Answer:

i don't get what I have to do

8 0
2 years ago
A hunter aims at a deer which is 40 yards away. Her cross- bow is at a height of 5ft, and she aims for a spot on the deer 4ft ab
shutvik [7]

Answer:

a)  θ₁ = 0.487º , b)   t = 0.400 s ,        x = 11.73 ft

Explanation:

For this exercise let's use the projectile launch relationships.

The initial height is I = 5 ft and the final height y = 4 ft

            y = y₀ + v_{oy} t - ½ g t²

The distance to the band is x = 40 yard (3 ft / 1 yard) = 120 ft

            x = v₀ₓ t

            t = x / v₀ₓ

We replace

             y –y₀ = v_{oy} x / v₀ₓ - ½ g x² / v₀ₓ²

             v_{oy} = v₀ sin θ

             v₀ₓ = vo cos θ

             

             y –y₀ = x tan θ - ½ g x² / v₀² cos² θ

                5-4 = 120 tan θ - ½ 32 120 / (300 2 cos2 θ)

                1 = 120 tan θ - 0.0213 sec² θ

Let's use the trigonometry relationship

               Sec² θ = 1 - tan² θ

                 1 = 120 tan θ - 0.0213 (1 –tan²θ)

                 0.0213 tan²θ + 120 tanθ -1.0213 = 0

                 

We change variables

          u = tan θ

          u² + 5633.8 u - 48.03 = 0

We solve the second degree equation

          u = [-5633.8 ±√(5633.8 2 + 4 48.03)] / 2

          u = [- 5633.8 ± 5633.82] / 2

           u₁ = 0.0085

           u₂= -5633.81

           u = tan θ

           θ = tan⁻¹ u

For u₁

           θ₁ = tan⁻¹ 0.0085

           θ₁ = 0.487º

For u₂

           θ₂ = -89.99º

The launch angle must be 0.487º

b) let's look for the time it takes for the arrow to arrive

         x = v₀ₓ t

         t = x / v₀ cos θ

         

         t = 120 / (300 cos 0.487)

         t = 0.400 s

The deer must be at a distance of

           v = 20 mph (5280 ft / 1 mi) (1 h / 3600s) = 29.33 ft / s

           x = v t

           x = 29.33 0.4

           x = 11.73 ft

3 0
2 years ago
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