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Vilka [71]
3 years ago
15

What happens to myosin and actin as sarcomeres relax?

Physics
1 answer:
Leokris [45]3 years ago
4 0
The myosin heads pull on the actin, bringing them closer together

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How do things rust? Is this chemical or mechanical weathering?
IrinaK [193]
I'll say that's mechanical weathering
6 0
3 years ago
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How is the surface area of an average person is 2m^2 in the chapter pressure
11Alexandr11 [23.1K]

Answer:

We have to show surface area =2m^2,with few conditions that is by considering Force =200000\ N and Pressure =100000\ Pa to be respectively.

Explanation:

The atmospheric pressure is =10^{5}\ Pa on Earth's surface.

The magnitude of the force exerted on a person by the atmosphere is =2\times 10^{5}\N (or)\ 200kN\ (or)\ 20\ ton.

Now to calculate surface area we can find it from pressure=\frac{force}{area} and re-arranging it to.

area=\frac{force}{pressure}

So plugging the values,

Surface area =\frac{20000}{10000}=2\ m^{2}

Hence from the above calculations we can say that surface area is 2m^2.

So the surface area of an average person can be said to have 2m^2, using the concept of pressure and force.

3 0
3 years ago
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A cylindrical container closed of both end has a radius of 7cm and height of 6cm A.)find the total surface area of the container
Natalka [10]

Given:

A cylindrical container closed of both end has a radius of 7cm and height of 6cm.

Explanation:

A.) Find the total surface area of the container.

  • A = 2πrh + 2πr²
  • A = 2(3.14)(7)(6) + 2(3.14)(7 × 7)
  • A = 263.76 + 307.72
  • A = 571.48

B.) Find the volume of the container.

  • V = πr²h
  • V = (3.14)(7×7)(6)
  • V = 923.16

Not sure huhuness.

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8 0
3 years ago
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Iron ball sinks in water but not in mercury. Why?
Zigmanuir [339]

Answer:

mercury is more dense

Explanation:

8 0
3 years ago
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A horizontal force of 200 N is applied to move a 55 kg television set across a 10 m level surface. What is the work done by the
vivado [14]

Answer:

The work done is "2000 J".

Explanation:

The given values are:

Force,

F = 200 N

Mass,

m = 55 kg

Displacement,

d = 10 m

Now,

The work done will be:

⇒  Work \ done= Force\times displacement

On substituting the given values, we get

⇒                     =200\times 10

⇒                     =2000 \ J

3 0
3 years ago
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