Answer:
10.337m/s2
Explanation:
F=ma
a=F/m
a = 92 / 8.9 = 10.337m/s2
<u>Answer: </u>
Balloon powered car works on the principle of Newtons III law. Escaping air from the balloon, the car accelerates forward. The reaction is the air behind the car, pushing against it, and with the same force car moves forward is the action.
<em>Some scientific questions are:</em>
1. What is the energy stored in the balloon?
Ans: Potential energy (Potential energy is stored in elastic balloon)
2. Which energy is used in balloon-powered car?
Ans: Kinetic energy. (Whenever the balloon escapes the air, potential energy is converted into Kinetic energy)
3. What is the principle involved in balloon powered car?
Ans: Newtons III law.
Answer:
Part 1: 0.3789
Part 2: 746 J
Part 3: 2.162 kW
Explanation:
Part 1:
Eff= 
Eff= 0.378873 ≈ 0/3789
Part 2:
W= 0.3789(1969)
W= 746 J
Part 3:
Power= 2162.3188 Watts
2162.3188 W-----> 2.162 kW
Answer:
The objects must be different temperatures.
Explanation:The objects must be different temperatures. eat will flow from Object 1 to Object 2 in examples 1, 2, and 4, and heat will flow from Object 2 to Object 1 in Example 3. Which factors affect heat transfer between a warm and a cool substance?
Answer:
The spring constant is 60,000 N
The total work done on it during the compression is 3 J
Explanation:
Given;
weight of the girl, W = 600 N
compression of the spring, x = 1 cm = 0.01 m
To determine the spring constant, we apply hook's law;
F = kx
where;
F is applied force or weight on the spring
k is the spring constant
x is the compression of the spring
k = F / x
k = 600 / 0.01
k = 60,000 N
The total work done on the spring = elastic potential energy of the spring, U;
U = ¹/₂kx²
U = ¹/₂(60000)(0.01)²
U = 3 J
Thus, the total work done on it during the compression is 3 J
