All categories

3 years ago

Name two types of small bodies that are found on the Kuiper belt.

Physics

1 answer:

uranmaximum [27]3 years ago

7 0

A penis and a vagina are found on Kuiper belt.

You might be interested in

I'll make you brainliest! EaSyQuEsTiOn pleaze ASAP hurry! Make you brainliest Promise!!!

inysia [295]

Answer:

It hit Earth like a really long time ago, so many rocks and soil should have been piled on top of the crater because of wind, rain, etc.

Also, it is really deep and really old so when it is old, it gets less visible to the naked eye.

8 0

2 years ago

We drive at a speed of 20 km/h for 3 hours. Then we drive 4 hours at 30 km/h. Calculate our average speed.

Afina-wow [57]

First speed = 20km/h

Time = 3 hours

Distance = 3×20

Second speed = 30km/h

Time = 4 hours

Distance = 4×30

Total distance = 60+120 = 180km

Total time = 3+4 = 7 hours

Average speed = 180/7

Hope this will help...

4 0

3 years ago

Read 2 more answers

The graph shows the federal budget from 1980 to 2010. In which period did the federal budget show the greatest deficit?

kodGreya [7K]

Answer:

2000 to 2010

Explanation:

sorry I'm just guessing

8 0

2 years ago

Arrange the distances between Earth and various celestial objects in order from least to greatest. Use the conversion table to h

Kaylis [27]

distance to the star Betelgeuse: 640 ly

As we know that

$1 ly = 63000 AU$

also we know that

$1AU = 1.5 \times 10^8 km$

$1 ly = 63000 (1.5 \times 10^8) = 9.45 \times 10^{12} km$

So the distance of Betelgeuse = 640 ly

$d_1 = 640 \times 9.45 \times 10^{12} = 6.05 \times 10^{15} m$

distance to the star VY Canis Majoris: $3.09 × 10^8 AU$

$d_2 = 3.09\times 10^8 \times 1.5 \times 10^8 km$

$d_2 = 4.64 \times 10^{16} km$

distance to the galaxy Large Magellanic Cloud: 49976 pc

$1 pc = 3.262 ly = 3.262 \times 9.45 \times 10^{12} km$

$1pc = 3.08 \times 10^{13} km$

now we have

$d_3 = 49976 \times 3.08 \times 10^{13}$

$d_3 = 1.54 \times 10^{18} km$

distance to Neptune at the farthest: 4.7 billion km

$d_4 = 4.7 \times 10^9 km$

now the order of distance from least to greatest is as following

1. distance to Neptune at the farthest

2. distance of Betelgeuse

3. distance to the star VY Canis Majoris

4. distance to the galaxy Large Magellanic Cloud

6 0

3 years ago

If the ankylosaurs starts running and accelerates at 1.3m/s^2 for 3 seconds how far does he make it before the velociraptor catc

sveta [45]

Acceleration is the change of velocity, and velocity is the change of distance. The opposite of finding change, or differentiation, is integration.

Acceleration = 1.3 m/s²

Velocity: ∫ 1.3 dx = 1.3x + c m/s

Distance: ∫ 1.3x dx = 1.3x²/2 + c m

Distance run: 1.3*3²/2 = 5.85 m

What bad thing happened?

7 0

3 years ago