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viva [34]
3 years ago
5

The following pairs of surfaces are pushed together with the same amount of force. Between which pair of surfaces will friction

be the greatest?
A. two pieces of sandpaper
B. two pieces of waxed paper
C. a painted surface and a piece of sandpaper
D. a painted surface and a piece of waxed paper


Juan and his friends want to build their own go-karts and race down their street. According to Newton’s Second Law of Motion, which of these will help Juan to win the race?
A. increasing the mass of his go-kart
B. increasing the amount of inertia the go-kart has
C. decreasing the net force applied to the go-kart
D. decreasing the mass of his go-kart
Physics
2 answers:
Aleks [24]3 years ago
5 0
A.  The friction between two pieces of sandpaper is greater than
the friction between any of the pairs of surfaces.

D.  Juan should decrease the mass of his go-kart.  Then any force
that pushes it forward will give it greater forward acceleration.
ozzi3 years ago
5 0

c. a painted surface and a piece of sandpaper

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Speedy Sue, driving at 34.0 m/s, enters a one-lane tunnel. She then observes a slow-moving van 160 m ahead traveling at 5.20 m/s
Zielflug [23.3K]

Answer:

there will be collision

Explanation:

v_{s} =  speed of sue = 34 m/s

v_{v} = speed of van = 5.20 m/s

v_{sv} = speed of sue relative to van  = v_{s} - v_{v} = 34 - 5.20 = 28.8 m/s

d_{s} = stopping distance after brakes are applied

D = distance between sue and van = 160 m

v_{f} = final speed of sue = 0 m/s

a = acceleration = - 1.80 m/s²

Using the kinematics equation

v_{f}^{2} = v_{o}^{2} + 2 a d_{s}

0^{2} = 28.8^{2} + 2 (1.80) d_{s}

d_{s} = 230.4 m

Since  d_{s} < D

hence there will be collision

7 0
3 years ago
A student drops an object out the window of the top floor of a high-rise dormitory.
seropon [69]

-- The acceleration due to gravity is 32.2 ft/sec² .  That  means that the
speed of a falling object increases by an additional 32.2 ft/sec every second.

-- If dropped from "rest" (zero initial speed), then after falling for 4 seconds,
the object's speed is (4.0) x (32.2) = <em>128.8 ft/sec</em>.

-- 128.8 ft/sec = <em>87.8 miles per hour</em>

Now we can switch over to the metric system, where the acceleration
due to gravity is typically rounded to 9.8 meters/sec² .

-- Distance = (1/2) x (acceleration) x (time)²

       D = (1/2) (9.8) x (4)² =<em>  78.4 meters</em>

-- At 32 floors per 100 meters,  78.4 meters = dropped from the <em>25th floor</em>.


The 5 points are certainly appreciated, but I do wish they were Celsius points.


3 0
3 years ago
A silver bar 0.125 meter long is subjected to a temperature change from 200 C to 100 C . What will be the length of the bar afte
dimulka [17.4K]
\Delta L= \alpha L_0 (T_f-T_i)

= (18 x 10^-6 /°C)(0.125 m)(100° C - 200 °C)

= -0.00225 m

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= 1.248
So your answer is B.
8 0
3 years ago
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