Question

he summit of Mount Everest is 8850 m above sea level. (a) How much energy would a 78 kg climber expend against the gravitational force (his weight) in climbing to the summit from sea level? (Your answer should suggest that work done against the gravitational force is a very small part of the energy expended in climbing a mountain.)

Answer 1

Answer:

The energy which is expend by the person is $U=6.7\times 10^{6}J$.

Explanation:

The formula for the potential energy due to the height of the object is as follows as;

U= mgh

Here, h is the height of the person, m is the mass of the object and g is the acceleration due to gravity.

It is given in the problem that a person is 8850 m above the sea level. 78 kg climber would expend energy against the gravitational force in climbing to the summit from sea level. Here, the person has potential energy as he is above the sea level.

Put h= 8850 m, m= 78 kg and  $g = 9.8 m s^{-2}$ and  in the above expression to get the value of energy.

U= (78)(9.8)(8850)

U= 6764940 J

$U=6.7\times 10^{6}J$

Therefore, the energy which is expend by the person is $U=6.7\times 10^{6}J$.