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mote1985 [20]
3 years ago
15

Which energy level of the outermost in aluminum

Physics
1 answer:
Eduardwww [97]3 years ago
8 0
The outermost energy level of an element are called the valence shell, that holds the valence electrons. they consist of  the highest energy level. In aluminum, the valence electrons are 3. <span />
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Which of Newton's laws explains why satellites need very little fuel to stay in oribit?
Angelina_Jolie [31]

Sattelites don't need any fuel to stay in orbit. The applicable law is...."objects in motion tend to stay in motion". Having reached orbital velocity, any such object is essentially "falling" around the earth. Since there is no (or at least very little) friction in the vacuum of space, the object does not slow.... It simply continues.


Sattelites in "low" earth orbit do encounter some friction from the very thin upper atmosphere, and they will eventually "decay".

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3 years ago
Determine the torque<br> produced by a perpendicular force of 75<br> N at the end of a 0.2 m wrench.
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Answer:c

Explanation:

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7 0
2 years ago
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3 years ago
If the x-component of a force vector is 5.17 newtons and its y-component is 8.80 newtons, then what is its magnitude?
olya-2409 [2.1K]

Answer:

10.21 N

Explanation:

As the force is a vector, it can be decomposed in two components perpendicular each other, so there is no projection of one component in the direction of the other.

When divided in this way, the magnitude of the resultant vector can be found simply applying trigonometry, as follows:

F² = Fx² + Fy² ⇒ F = √(Fx)²+(Fy)²

Replacing by Fx= 5.17 N and Fy = 8.8 N, we get:

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3 0
3 years ago
What fraction of the total energy of a SHO is kinetic when the displacement is one third the amplitude
Bas_tet [7]

Answer:

The fraction of kinetic energy to the total energy is \frac{K}{T}=\frac{8}{9}.

Explanation:

displacement is one third of the amplitude.

Let the amplitude is A.

x= A/3

The kinetic energy of the body executing SHM is

K = 0.5 mw^2(A^2 - x^2)\\\\K = 0.5 m w^2 \left ( A^2 -\frac{A^2}{9} \right )\\\\K = 0.5 mw^2\times \frac{8A^2}{9}......(1)

The total energy is

T =0.5 mw^2A^2 ..... (2)

Divide (1) by (2)

\frac{K}{T}=\frac{8}{9}

5 0
3 years ago
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