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3 years ago

Which phrase could be represented by this expression? 6(t + 9 )

1 answer:

7 0

You multiply everything in the parentheses by the outside number. And since you are multiplying, it would eliminate b & d. So, the answer is A.

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Anita is making a curtain to surround a table. She bought 3 1/4 yards of fabric. Her total cost was $13. What was the cost per y

Ratling [72]

3.25y=13. Isolate y by dividing both sides of the equation by 3.25. So 3.25y/3.25=13/3.25. Your answer is therefore 13/3.25, or 4

7 0

3 years ago

Read 2 more answers

What number is greater 0.111 or 1.001. also 1.11 or 1.01

Paul [167]

1.001 is greater than 0.111 because the 1 is automatically greater than zero. 1.11 is greater than 1.01 because there is a place in the tenths place in 1.11 but none for 1.01.

4 0

3 years ago

Read 2 more answers

Xiao teacher asked him to rewrite the sum 60+90 as the product of the GCF of the two numbers and a sum Xiao wrote 3(20+30) what

GrogVix [38]

$The\ mistake:GCF(60;\ 90)\ isn't\ 3\ just\ 30.\\\\Correct\ answer:60+90=30(2+3)$

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3 years ago

An arc with length 5 pi over 4 inches is formed by a 15 degree central angle what is the radius of the circle

Natalka [10]

Answer:

Radius of the circle is 15 inches.

Step-by-step explanation:

Relation between length of arc, radius and the angle subtended by the arc on center is:

$\theta = \dfrac{l}{r} ..... (1)$

where $\theta$ is the central angle in radians subtended by arc

$l$ is the length of arc

$r$ is the radius of arc

We are Given the following details:

$l = \dfrac{5\pi}{4}\ inch$

$\theta = 15^\circ$

We know that $\pi \ radians = 180 ^\circ$

Converting $\theta$ to radians:

$\theta =\dfrac{\pi}{180} \times 15$ radians

Putting the values of $\theta$ and $l$ to find the value of $r$

$\dfrac{\pi}{180} \times 15 = \dfrac{5\pi}{4r}\\\Rightarrow r = \dfrac{45}{3} \\\Rightarrow r = 15 \ inches$

Hence, Radius of the circle is 15 inches.

6 0

3 years ago

Product of two natural numbers p and q is 590 and their hcf is 59. how many set of values of p and q is possible

djverab [1.8K]

$\text{Let the product of two natural numbers p and q is 590, and their HCF is 59}\\
\\
\text{we know that the product of LCM and HCF of any two numbers is equal}\\
\text{to the product of the numbers. that is}\\
\\
\text{HCF}\times \text{ LCM}=p\times q\\
\\
\Rightarrow 59 \times \text{LCM}=590\\
\\
\Rightarrow \text{LCM}=\frac{590}{59}\\
\\
\Rightarrow \text{LCM}=10\\
\\
\text{for any two natural numbers, their Least Common Multiple (LCM) is always}$

$\text{greater than their HCF.}\\
\\
\text{but here we can see that }LCM$

Hence there is no such natural numbers exist.

7 0

3 years ago