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alex41 [277]
3 years ago
9

How much power does an electric device use if the current is 36.0 amps and the resistance is 3.9 ohms?

Physics
1 answer:
dsp733 years ago
8 0
<span>Question: How much power does an electric device use if the current is 36.0 amps and the resistance is 3.9 ohms? </span>

How?: 

Equation: P = I^2 R          

Meanings:
P = Power in Watts
I = Current in Ampere
R = Resistance in ohms.

Plugged in: P = 36^2<span> x 3.9 = 5054.4
 
Answer: P= </span>5100 watts.

HOPE THIS HELPS! ^_^
<span>  </span>
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Adjacent antinodes of a standing wave on a string are 15.0 cmapart. A particle at an antinode oscillates in simpleharmonic motio
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Answer:

a)   D = 15 cm , b)  λ = 30.0 cm , c) 0.0850 cm, d) v = 400 cm / s , e)    v = 80.43 cm / s , v = -80.43 cm / s, f)   D₂= 7.5 cm

Explanation:

Standing waves form when two waves of the same frequency travel in opposite directions,

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B) the wavelength is the distance for which the wave repeats itself, in the case of a standing wave, the distance between two nodes is lamita of the wavelength.

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C) the amplitude of each wave is 0.0850 cm, the amplitude of the standing wave is double A = 0.17 cm

D) Let's use the speed ratio

        v =  λ f

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        v =  λ / T

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E) the transverse speeds are the speed of the oscillatory movement

       y = A cos (wt)

 

      w = 2π f = 2π / T

      w = 2π / 0.0750

      w = 83.78 rad / s

     

      y = 0.850 cos (83.78 t)

Speed ​​is

      v = dy / dt

      v = -A w cost wt

      v = - 0.850 83.78 cos (83.78 t)

      v = -80.43 cos (83.78 t)

The maximum speed when the cosine values ±1

       v = 80.43 cm / s

       v = -80.43 cm / s

F) if we draw a drawing, the distance between two nodes is half the wavelength, at the distance between an antinode synod is half this, it occupies a quarter of the wavelength

      D₂ = ¼  λ

      D₂ = 30.0/4

      D₂= 7.5 cm

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