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Natasha2012 [34]

2 years ago

11

The guitarist shortens the oscillating length of the properly tuned D-string by 0.15 m by pressing on the string with a finger.

What is the fundamental frequency, in hertz, of the new tone that is produced when the string is plucked?

1 answer:

Greeley [361]2 years ago

3 0

Answer:

The fundamental frequency is "190.52 Hz".

Explanation:

The given question is incomplete, please find attachment of the complete problem.

The given values are:

Frequency,

f = 146.8 Hz

Length of D-string,

L = 0.61

As we know,

⇒ $f = \frac{v}{2L}$

On putting the given values, we get

⇒ $146.8 = \frac{v}{(2\times 0.61)}$

⇒ $v=146.8\times 1.22$

⇒ $v=179 \ m/s$

So,

The new length will be:

⇒ $f = \frac{179}{(2\times 0.47)}$

⇒ $=\frac{179}{0.94}$

⇒ $=190.52 \ Hz$

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2 years ago

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Answer:

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2 years ago

An object has a force of 10 newtons from the right and 17 newtons from the left. Once the object starts moving toward the right,

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$\Delta H=n\times \Delta H_{fusion}$

where,

$\Delta H$ = enthalpy change = ?

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Now put all the given values in the above expression, we get

$\Delta H=1.11\times 10^3mole\times 6010J/mole$

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