Question

The guitarist shortens the oscillating length of the properly tuned D-string by 0.15 m by pressing on the string with a finger. What is the fundamental frequency, in hertz, of the new tone that is produced when the string is plucked?

Answer 1

Answer:

The fundamental frequency is "190.52 Hz".

Explanation:

The given question is incomplete, please find attachment of the complete problem.

The given values are:

Frequency,

f = 146.8 Hz

Length of D-string,

L = 0.61

As we know,

⇒ $f = \frac{v}{2L}$

On putting the given values, we get

⇒ $146.8 = \frac{v}{(2\times 0.61)}$

⇒       $v=146.8\times 1.22$

⇒       $v=179 \ m/s$

So,

The new length will be:

⇒  $f = \frac{179}{(2\times 0.47)}$

⇒     $=\frac{179}{0.94}$

⇒     $=190.52 \ Hz$