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Dennis_Churaev [7]
3 years ago
11

Which composition of water moves to begin a deepwater current?

Physics
1 answer:
Paraphin [41]3 years ago
6 0

<u>Answer:</u>

<h2>Cold, Salty water.</h2>

<u>Explanation:</u>

The cold, salty ocean water is denser than the warmer water. Because of higher density, cold water sinks into the bottom of the ocean while warm water remains at the surface.

The sinking of the cold water at depth moving away from the surface generates deepwater currents by a process called upwelling. These deepwater currents bring the nutrient-rich water at the surface providing food and nutrients to marine life.


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I think it is c density and temperature
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4 years ago
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Now suppose the initial velocity of the train is 4 m/s and the hill is 4 meters tall. If the train has a mass of 30000 kg, what
hoa [83]

Answer:

<h2>187,500N/m</h2>

Explanation:

From the question, the kinectic energy of the train will be equal to the energy stored in the spring.

Kinetic energy = 1/2 mv² and energy stored in a spring E = 1/2 ke².

Equating both we will have;

1/2 mv² = 1/2ke²

mv² = ke²

m is the mass of the train

v is the velocity of then train

k is the spring constant

e is the extension caused by the spring.

Given m = 30000kg, v = 4 m/s, e = 4 - 2.4 = 1.6m

Substituting this values into the formula will give;

30000*4² =  k*1.6²

k = \frac{30,000*16}{1.6^2}\\ \\k = \frac{480,000}{2.56}\\ \\k = 187,500Nm^{-1}

The value of the spring constant is 187,500N/m

7 0
3 years ago
Two projectile launchers are beside one another on level ground. Both launchers are directed at the same angle with respect to g
kakasveta [241]

Answer:

(a) Projectile B will travel 4 times as far as projectile A prior to landing

Explanation:

Initial velocity = v

Angle at which the projectile is shot at = θ

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Range of a projectile is given by

R=\frac {v^{2}\sin 2\theta}{g}

When Initial velocity = v

R_A=\frac{v^{2}\sin 2\theta}{g}

When Initial velocity = 2v

R_B=\frac{(2v)^{2}\sin 2\theta}{g}\\\Rightarrow R_B=\frac{4v^2\sin 2\theta}{g}

Dividing the equtions, we get

\frac{R_A}{R_B}=\frac{\frac{v^{2}\sin 2\theta}{g}}{\frac{4v^2\sin 2\theta}{g}}

Here, the angle at which the projectiles are fired at are equal.

\frac{R_A}{R_B}=\frac{1}{4}\\\Rightarrow R_B=4R_A

Hence, projectile B will travel 4 times as far as projectile A prior to landing

7 0
3 years ago
Forces start and change the motion of an object. Question 1 options: True False
Vlad1618 [11]
I think it’s true I may be wrong tho
8 0
3 years ago
how does distance change when the amount of effort force is increasesd while the amount of work done remains the same?
nlexa [21]
Could you supply u with some answer choices please?
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4 years ago
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