Answer:
5.9 km/hour
Explanation:
divide 12.5 by 2.1 and the answer is 5.9
Answer: 3.55 s and 0.83 s
Explanation:
The height (in feet) of the softball is given by:
s(t)=-16t²+70t+3
we need to find the time when the ball is 50 feet above the ground:
⇒50 = -16t²+70t+3
we need to solve the quadratic equation
⇒16t²-70t+47 = 0
This gives two values of time: 3.55 s and 0.83 s
Answer:
v = - 1,715 m / s
, x = 0.0156 m
Explanation:
This is an oscillatory movement exercise, which is described by the expression
x = A cos (wt + Ф)
we can assume that the block is released from its maximum elongation, so the phase constant (Ф) is zero
As we are told that the stone does not affect the movement of the spring mass system, the amplitude and angular velocity do not change, in the upward movement the stone is attached to the mass, but in the downward movement the mass has an acceleration greater than g leave the stone behind, let's look for time, for this we use the definition of speed and acceleration
v = dx / dt
v = - A w sin wt
a = - Aw² cos wt
a = -g
-g = - Aw² cos wt
wt = cos⁻¹ (g / Aw²)
t = 1 / w cos⁻¹ (g / Aw²)
angular velocity and frequency are related
w = 2π f
w = 2π 4
w = 8π rad / s
remember that the angles are in radians
t = 1 / 8π cos⁻¹ (9.8 / (0.07 64π²))
t = 0.039789 1.3473
t = 0.0536 s
let's find the speed for this time
v = - A w sin wt
v = - 0.07 8π sin (8π 0.0536)
v = - 1,715 m / s
the distance is
x = A cos wt
x = 0.07 cos (8π 0.0536)
x = 0.0156 m
Answer:
Increases
Explanation:
For a given force, as the time increases, the impulse related to that force increases also.
Impulse and time are directly related to one another. Impulse is mathematically given as:
I = F t
I is the impulse
F is the force
t is the time taken
So, as both force and time increases, the value of the impulse must increase.
Hi there,
The items labelled 6 are part of a trend line but are connected to data points. Hence the answer to this question would be A) Data Points
I hope this helps, and good luck in your future studies :)
Sincerely,
Dus4nR
