I think your answer is probably expert but I may be wrong
If the rod is in rotational equilibrium, then the net torques acting on it is zero:
∑ τ = 0
Let's give the system a counterclockwise orientation, so that forces that would cause the rod to rotate counterclockwise act in the positive direction. Compute the magnitudes of each torque:
• at the left end,
τ = + (50 N) (2.0 m) = 100 N•m
• at the right end,
τ = - (200 N) (5.0 m) = - 1000 N•m
• at a point a distance d to the right of the pivot point,
τ = + (300 N) d
Then
∑ τ = 100 N•m - 1000 N•m + (300 N) d = 0
⇒ (300 N) d = 1100 N•m
⇒ d ≈ 3.7 m
Answer:
no easy sooooo easy like cmon now
Answer:
Option B. inertia
Explanation:
Inertia can be explained as the property of a body due to which the body resists any change in its form or shape.
The given case complies with Newton's first law or Law of inertia which says_ a body in motion will remain in that state of motion or at rest will continue to be in that stationary until it comes under the action of some external force.
Therefore, a meteor moving through outer space will continue on that path until acted upon by an external force.
Assume the ball was thrown at ground level, so its initial position vector is . Let denote the ball's initial speed and the angle at which the ball is thrown.
Over time, its position changes according to , where the components are determined by
where is the acceleration due to gravity. We know the ball is in the air for 4.5 seconds and that it travels a horizontal distance of 45 meters, which means
Divide the second equation by the first to eliminate , and we can solve for , expecting some solution within :
Then plugging this into either equation above will tell us the ball's initial speed: