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adelina 88 [10]
3 years ago
8

If a truck is travelling east on a straight road and travels 100 meters in 25s what is the truck's velocity?

Physics
1 answer:
Slav-nsk [51]3 years ago
3 0

Answer:

Velocity of the truck, v = 4 m/s                                                            

Explanation:

It is given that,

Distance covered by the truck, d = 100 m

Time taken by the truck, t = 25 s

Let v is the velocity of the truck. We know that the velocity is a vector quantity. Mathematically, it is given by :

v=\dfrac{d}{t}

v=\dfrac{100\ m}{25\ s}

v = 4 m/s

So, the velocity of the truck is 4 m/s. Hence, this is the required solution.

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Answer:

The forces are balanced on both animals because they are not moving

More importantly than not moving is not <u>accelerating.</u>

Explanation:

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Define what is energy and work​
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8 0
3 years ago
How long does it take anya to cover the distance of 5.00 miles ?
sammy [17]
Here is the full information about the question. <span>Ilya and Anya each can run at a speed of 8.50mph and walk at a speed of 3.50 mph . They set off together on a route of length 5.00 miles . Anya walks half of the distance and runs the other half, while Ilya walks half of the time and runs the other half.
the calculation would be:
</span><span>
t = d / s </span>
<span>t = 2.5 (half of the total distance) / 8.5 (speed of running) </span>
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<span>for the walking part... </span>

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5 0
3 years ago
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3 0
3 years ago
Joe and Max shake hands and say goodbye. Joe walks east 0.40 km to a coffee shop, and Max flags a cab and rides north 3.65 km to
katen-ka-za [31]

Answer:

3.67 km

Explanation:

Joe distance towards coffee shop is,

OB=0.40 km

And the Max distance towards bookstore is,

OA=3.65 km

Now the distance between the Joy and Max will be,

By applying pythagorus theorem,

AB=\sqrt{OB^{2}+OA^{2}}

Substitute 0.40 km for OB and 3.65 km for OA in the above equation.

AB=\sqrt{0.40^{2}+3.65^{2}}\\AB=\sqrt{13.4825} \\AB=3.67 km

Therefore the distance between there destination is 3.67 km.

6 0
3 years ago
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