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Sergeeva-Olga [200]
3 years ago
9

professional baseball player nolan ryan could pitch a baseball at approximately 160.0 km/h. at that average velocity, how long d

id it take a ball thrown by ryan to reach home plate, which is 18.4 m from the pitcher’s mound? compare this with the average reaction time of a human to a visual stimulus, which is 0.25 s.
Physics
2 answers:
Margarita [4]3 years ago
6 0

Answer:

0.41 s

Explanation:

Parameters given:

Speed of ball, v = 160 km/h

Distance between Ryan and the home plate, d = 18.4 m = 0.0184 km

Speed is given as the time rate of change of distance. Mathematically:

Speed = \frac{distance}{time} \\\\\\v = \frac{d}{t}

Therefore, time will be:

t = \frac{d}{v}

t = \frac{0.0184}{160} \\\\\\t = 0.000115 hr = 0.41 s

The time it will take the ball to reach the home plate is 0.41 s.

Comparing this to the average reaction time of humans to visual stimulus (0.25 s), we see that the time it will take the ball is greater than the reaction time.

This implies that an average person should be able to track the motion of the ball as it moves towards the home plate.

prohojiy [21]3 years ago
4 0

Answer:

t = 0.4 s

Explanation:

Assuming that we can neglect the influence of gravity, the ball travels at a constant speed along a straight line, between the pitcher's mound and the home plate.

We can apply the definition of average velocity, as follows:

v = xf-xo /tfin-to

If we choose to = 0, and xo = 0 (coincident with the mound's  location), we can simply put:

t = xf / v (1)

As we have x and v in different units, we can convert v from km/h to m/s, as follows:

v= 160 Km/h * (1 h/ 3600 sec) * (1000 m / 1 Km) = 44.4 m/s

Replacing in (1):

t = 18.4 m / 44.4 m/s = 0.4 s

As the average reaction time of a human to a visual stimulus, is roughly 0.25 sec, the time needed for the ball to travel is just 1.25 of this time.

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Answer:

Option (2)

Explanation:

From the figure attached,

Horizontal component, A_x=A\text{Sin}37

A_x=12[\text{Sin}(37)]

     = 7.22 m

Vertical component, A_y=A[\text{Cos}(37)]

    = 9.58 m

Similarly, Horizontal component of vector C,

C_x  = C[Cos(60)]

     = 6[Cos(60)]

     = \frac{6}{2}

     = 3 m

C_y=6[\text{Sin}(60)]

    = 5.20 m

Resultant Horizontal component of the vectors A + C,

R_x=7.22-3=4.22 m

R_y=9.58-5.20 = 4.38 m

Now magnitude of the resultant will be,

From ΔOBC,

R=\sqrt{(R_x)^{2}+(R_y)^2}

   = \sqrt{(4.22)^2+(4.38)^2}

   = \sqrt{17.81+19.18}

   = 6.1 m

Direction of the resultant will be towards vector A.

tan(∠COB) = \frac{\text{CB}}{\text{OB}}

                  = \frac{R_y}{R_x}

                  = \frac{4.38}{4.22}

m∠COB = \text{tan}^{-1}(1.04)

             = 46°

Therefore, magnitude of the resultant vector will be 6.1 m and direction will be 46°.

Option (2) will be the answer.

6 0
3 years ago
You hang a heavy ball with a mass of 10 kg from a gold wire 2.6 m long that is 1.6 mm in diameter. You measure the stretch of th
PolarNik [594]

<u>Answer:</u> The Young's modulus for the wire is 6.378\times 10^{10}N/m^2

<u>Explanation:</u>

Young's Modulus is defined as the ratio of stress acting on a substance to the amount of strain produced.

The equation representing Young's Modulus is:

Y=\frac{F/A}{\Delta l/l}=\frac{Fl}{A\Delta l}

where,

Y = Young's Modulus

F = force exerted by the weight  = m\times g

m = mass of the ball = 10 kg

g = acceleration due to gravity = 9.81m/s^2

l = length of wire  = 2.6 m

A = area of cross section  = \pi r^2

r = radius of the wire = \frac{d}{2}=\frac{1.6mm}{2}=0.8mm=8\times 10^{-4}m      (Conversion factor:  1 m = 1000 mm)

\Delta l = change in length  = 1.99 mm = 1.99\times 10^{-3}m

Putting values in above equation, we get:

Y=\frac{10\times 9.81\times 2.6}{(3.14\times (8\times 10^{-4})^2)\times 1.99\times 10^{-3}}\\\\Y=6.378\times 10^{10}N/m^2

Hence, the Young's modulus for the wire is 6.378\times 10^{10}N/m^2

3 0
3 years ago
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Blababa [14]
It evaporates into a vapor

  ~~~hope this helps~~~
~~have a beautiful day~~
            ~davatar~
3 0
3 years ago
ANSWER FAST PLEASE HELP
KengaRu [80]

Answer:

B. 175 N

Explanation:

Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.

Mathematically, net force is given by the formula;

Fnet = Fapp + Fg

Where;

Fnet is the net force

Fapp is the applied force

Fg is the force due to gravitation

In this scenario, we observed that both forces are acting in the same direction.

Therefore:

Net force = 100 N + 75 N

Net force = 175 Newton

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Lina20 [59]

Answer:

The answer to this question can be defined as follows:

Explanation:

Therefore the 4th harmonicas its node is right and over the pickup so, can not be captured from 16.25, which is 1:4 out of 65. Normally, it's only conceptual for the certain harmonic, this will be low, would still be heard by the catcher.

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