Answer:
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Explanation:
(108Hs) is a synthetic element, and thus a standard atomic weight cannot be given. Like all synthetic elements, it has no stable isotopes. The first isotope to be synthesized was 265Hs in 1984. There are 12 known isotopes from 263Hs to 277Hs and 1–4 isomers. The most stable isotope of hassium cannot be determined based on existing data due to uncertainty that arises from the low number of measurements. The confidence interval of half-life of 269Hs corresponding to one standard deviation (the interval is ~68.3% likely to contain the actual value) is 16 ± 6 seconds, whereas that of 270Hs is 9 ± 4 seconds. It is also possible that 277mHs is more stable than both of these, with its half-life likely being 110 ± 70 seconds, but only one event of decay of this isotope has been registered as of 2016.[1][2].
Answer:
1 mole=6.023×10^23 molecules
3.04×10^23 molecules× value of 1 mole
Explanation:
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Answer:
2. 110.
Explanation:
- Kindly find the attached image.
From the solubility curve, you can find that at 45°C to make a saturated solution of this salt, you should add 110 g of NaNO₃.
- So, the right choice: 2. 110.
Answer
is: the molar mass of a covalent compound is 90.4 g/mol.
<span>
m(compound) = 0.486 g.
m(water) = 25 mL </span>· 1 g/mL = 25 g ÷ 1000 g/kg = 0.025 kg.<span>
ΔT = 0°C - (-0.40°C) = 0.40°C.</span>
Kf(H₂O) = 1.86°C/m.
M(compound) = Kf · m(compound<span>) /
m(water) · ΔT.
M</span>(compound)<span>= 1.86°C/m · 0.486 g /
(0.025 kg · 0.4°C).
M</span>(compound) = 90.4 g/mol.
Answer:
Acid-Catalyzed Ester Hydrolysis
Explanation:
Fischer Esterification is a reversible reaction and the Le Châteliers principle can be used for the reaction to be completed. For the reverse reaction of Fischer Esterification, using the hydrolysis of ethyl ethanoate, the steps involved are:
1) An hydrogen ion is added to the ester and one of the lone pairs on the oxygen double-bonded to the carbon atom takes the hydrogen ion.
2) The lone pairs on the oxygen of a water molecule takes the positive charge on the carbon atom.
3) The hydrogen ion is transferred from one oxygen atom to another.
4) Then an ethanol molecule is released (one of the products).
5) Reaction with a water molecule releases hydrogen from the oxygen and the other product (ethanoic acid) is formed.
