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Viefleur [7K]
4 years ago
13

Give the name of the following molecule

Chemistry
2 answers:
shutvik [7]4 years ago
7 0

Answer:

\boxed{Heptene}

Explanation:

Double Bond => An Alkene molecule

So, the suffix will be "-ene"

7 Carbons => So, we'll use the prefix "Hept-"

Combining the suffix and prefix, we get:

=> Heptene

kotegsom [21]4 years ago
5 0

Answer:

\boxed{\mathrm{Heptene}}

Explanation:

Alkenes have double bonds. The molecule has one double bond.

Suffix ⇒ <em>ene</em>

The molecule has 7 carbon atoms and 14 hydrogen atoms.

Prefix ⇒ <em>Hept </em>(7 carbons)

The molecule is Heptene.

\mathrm{C_7H_{14}}

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What is the density of a liquid if it's volume is 125 mL and it's mass is 50g?
masha68 [24]

Answer:

0.4g/ml

Explanation:

density= mass/volume

density=50g/125ml

density=0.4g/ml

6 0
3 years ago
Use the solubility generalizations on the information page to predict if one or more precipitates will form when aqueous solutio
neonofarm [45]

Answer:

3 (NH4)2SO4(aq) + 2 Al(NO3)3(aq) → 6 NH4NO3(aq) + Al2(SO4)3(aq)

Explanation:

In solubility rules, all ammonium and nitrates ions are solubles and all sulfates are soluble except the sulfates that are produced with Ca²⁺, Sr²⁺, Ba²⁺, Ag⁺ and Pb²⁺. That means the NH4NO3 and the Al2(SO4)3 produced are both <em>soluble and no precipitate is predicted. </em>

The reaction is:

<h3>3 (NH4)2SO4(aq) + 2 Al(NO3)3(aq) → 6 NH4NO3(aq) + Al2(SO4)3(aq)</h3>
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3 years ago
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netineya [11]

Answer:

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7 0
3 years ago
Imagine this scenario. All of the trees and plants are removed from a steep mountainside how would the removal of the trees and
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Read 2 more answers
A 125-mL sample of an aqueous solution of the protein ovalbumin from chicken egg white contains 1.31 g of the dissolved protein
Stella [2.4K]

The molar mass of the protein is 45095 g/mol.

The mass of a sample of a chemical compound divided by the quantity, or number of moles in the sample, measured in moles, is known as the molar mass of that compound.

The expression of molar mass of protein is

M₂ = (W₂/P) (RT/V)

Given;

W₂ = 1.31g

P = 4.32 torr = 5.75 X 10⁻³ bar

R = 0.083 Lbar/mol/K

T = 25°C = 298.15 K

V = 125 ml = 0.125 L

Putting all the values in the above formula

M₂= (1.31 g/5.75 X 10⁻³ bar) X (0.083 Lbar/mol/K X 2)/0.125 L)

M₂ = 45095 g/mol

Thus, the molar mass of the protein is 45095 g/mol.

Learn more about the Molar mass with the help of the given link:

brainly.com/question/22997914

#SPJ4

7 0
1 year ago
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