Answer:
Explanation:
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In this case, since one mole of ethanol release 8,842 J per 1 mole of ethanol, we can write:
Thus, since we need the energy released by 982.6 g of ethanol, we compute the moles in such mass of fuel:
Therefore, the result is:
Which in kJ is:
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Kinetic energy is energy that transfers energy by <span>net force which causes it to speed up and that causes more kinetic energy to be added . kinetic energy depends on mass and motion </span><span />
Answer
is: the molar mass of a covalent compound is 90.4 g/mol.
<span>
m(compound) = 0.486 g.
m(water) = 25 mL </span>· 1 g/mL = 25 g ÷ 1000 g/kg = 0.025 kg.<span>
ΔT = 0°C - (-0.40°C) = 0.40°C.</span>
Kf(H₂O) = 1.86°C/m.
M(compound) = Kf · m(compound<span>) /
m(water) · ΔT.
M</span>(compound)<span>= 1.86°C/m · 0.486 g /
(0.025 kg · 0.4°C).
M</span>(compound) = 90.4 g/mol.
When the concentration is expressed in ppm, that means parts per million. It is also equivalent to mg/L. For this problem, we do stoichiometric calculations. We manipulate the units by cancelling like units if they appear in the numerator and denominator side until we come with the amount of solid Ca(OCl)2 needed. The solution is as follows:
40 mg/L * (1 L/1000 mL) * 50 mL * (1 g/1000 mg) * (1 mol OCl⁻/51.452 g) * (1 mol Ca(OCl)₂/ 2 mol OCl⁻) * (142.983 g Ca(OCl)₂/mol) * 0.95 = 2.64×10⁻3 g or 2.64 mg.
Therefore, you would need 2.64 mg of solid Ca(OCl)₂.
