Answer:
Cu + 4HNO3 ---> Cu(NO3)2 + 2NO2 + 2H2O.
Explanation:
Balancing:
Cu + 4HNO3 ---> Cu(NO3)2 + 2 NO2 + 2H2O.
E=hv
=6.625×10^-34Js^-1×1.97×10^8s^-1
Cancel sec inverse.
=13.05×10^-26.
Answer:
Three half lives corresponds to (12)3 . So a 18 quantity of the original isotope is retained. And the percentage of quantity of a radioactive material that remains after 5 half-lives will be . ∴NN0×100=10032=3.125.
Answer:
heterogeneous and homogeneous
Explanation:
la po ba abc?