Hrxn = Q reaction / mol of reaction
mol of reaction = M * V = 10 * 1 = 10 mmol = 0.01 mol
Q water = m * C * (Tf - Ti)
= (10 + 10) (4.184) (26-20) = 502.08 J
Q reaction = - Q water = -502.08 J
Hrxn = -502.08 / (0.01) = - 50208 J = - 50.21 kJ/mol
Answer:
11.25moles of CO2
Explanation:
First, let us generate a balanced equation for the reaction of propane to produce CO2. This reaction called Combustion. It is a reaction in which propane burns in air (O2) to produce CO2 and H20. The equation is given below:
C3H8 + 5O2 —> 3CO2 + 4H2O
From the equation,
1mole of C3H8 produced 3moles of CO2.
Therefore, 3.750 moles of C3H8 will produce = 3.750 x 3 = 11.25moles of CO2
calcium,phosphorus,potassium,and sulfer
