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GarryVolchara [31]
3 years ago
14

A video game usually costs $49.95, but it’s on sale for 20% off. What is the discount amount? What is the sale price for this it

em? A. discount: $4.99, sale price: $44.96 B. discount: $9.95, sale price: $40.00 C. discount: $9.99, sale price: $39.96 D. discount: $20.00, sale price: $29.95
Mathematics
2 answers:
satela [25.4K]3 years ago
7 0

Answer:

the discount amount is $9.99

the sale price for the video game is $40


The answer is C.

Best of luck to you my dear.

Step-by-step explanation:

49.95x.2= 9.99


49.99-9.99= 40

Valentin [98]3 years ago
7 0

Answer: 1($5.99)2($7.79)3($3.41)

Step-by-step explanation:

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A private school opened in 2005 with an initial enrollment of 85 students. The enrollment has increased by an average of 18 stud
mafiozo [28]
<span>1. Let t = time in years, with t = 0 representing the year 2005. Let f(t) = the number of students enrolled at the private school and g(t) = the number of students enrolled at the public school. Create the two functions to represent the situation.

f(t) = 85 + 18t </span>⇒ y = 85 + 18x<span>
g(t) = 95 + 15t </span>⇒ y = 95 + 15x

y = y
85 + 18x = 95 + 15x
18x - 15x = 95 - 85
3x = 10
x = 10/3
x = 3 1/3

y = 85 +18(10/3) = 85 + 180/3 = 85 + 60 = 145
y = 95 + 15(10/3) = 95 + 150/3 = 95 + 50 = 145

x = 10/3 or 3 1/3
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4 0
3 years ago
A fish was swimming LaTeX: 2\frac{1}{2}2 1 2 feet below the water's surface at 1:00 p.M. Three hours later, the fish was at a de
marin [14]

Answer:

\frac{23}{4} feet

Step-by-step explanation:

The depth of the fish to the surface of water at 1:00 pm = 2 \frac{1}{2} feet

                                                                             =   \frac{5}{2} feet

The depth of the fish to its initial position at 4:00 pm = 3 \frac{1}{4} feet

                                                                              = \frac{13}{4} feet

The position of the fish with respect to the water's surface at 4:00 pm = the depth of the fish to the surface of water at 1:00 pm + the depth of the fish to its initial position at 4:00 pm

                                        =  \frac{5}{2} + \frac{13}{4}

                                        = \frac{10 + 13}{4}

                                         = \frac{23}{4}

The position of the fish with respect to the water's surface at 4:00 pm is \frac{23}{4} feet.

8 0
2 years ago
Need Help question is in the photo.​
san4es73 [151]

Answer:D,E

Step-by-step explanation:

9/3=3

36=9×4

3 0
2 years ago
What is the equivalent expression (2×6)+(8×4)+1​
ZanzabumX [31]

Answer:

45

Step-by-step explanation:

4 0
3 years ago
Need help ASAP <br> questions in the pics i have sent
Cloud [144]

Answer:

Step-by-step explanation:

Picture 1

In right triangle ABC,

Side AB is the opposite side of angle C.

Picture 2

In triangle MKL,

tan(∠M) = \frac{\text{Opposite side}}{\text{Adjacent side}}

             = \frac{KL}{KM}

             = \frac{15}{8}

Option (1) is the answer.

Picture 3

In ΔXYZ,

sin(∠Z) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

            = \frac{XY}{XZ}

For the length of XY we will apply Pythagoras theorem in ΔXYZ,

XZ² = XY² + YZ²

XY² = XZ² - YZ²

      = (40)² - (32)²

XY = √576

     = 24

sin(Z) = \frac{24}{40}

sin(Z) = \frac{3}{5}

Picture 4

In right triangle DEF,

Cos(D) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

           = \frac{EF}{DF}

           = \frac{75}{72}

           = \frac{25}{24}

Picture 5

In ΔABC,

tan(63°) = \frac{\text{Opposite side}}{\text{Adjacent side}}

tan(63°) = \frac{BC}{AB}

AB = \frac{BC}{\text{tan}(63)}

AB = \frac{8}{\text{tan}(63)}

AB = 4.0762 ≈ 4 m

Option (3) will be the answer.

7 0
3 years ago
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