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galina1969 [7]
3 years ago
7

Americium-241 is a radioactive substance used in smoke detectors. The half life of americium is 432 years. If a smoke detector i

nitially contains 1 gram of Americium 241, how much will remain in 432 years? A) 0.5g B) 1.0g C) 1.5g D) 2.0g
Chemistry
1 answer:
aksik [14]3 years ago
7 0
<span>The half life of americium is 432 years. That means that after 432 years only half(1/2) of initial amount will be left.
If we had 1 g, then after 432 years we will have only half of it.
1g*1/2=1/2 g=0.5 g
Answer is </span><span>A) 0.5g</span>
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<u>Answer:</u> The value of K_c for the given reaction is 1.435

<u>Explanation:</u>

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Given mass of N_2O_4 = 9.2 g

Molar mass of N_2O_4 = 92 g/mol

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Putting values in above equation, we get:

\text{Molarity of solution}=\frac{9.2g}{92g/mol\times 0.50L}\\\\\text{Molarity of solution}=0.20M

For the given chemical equation:

                 N_2O_4(g)\rightleftharpoons 2NO_2(g)

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<u>At eqllm:</u>     0.20-x        2x

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Equilibrium concentration of N_2O_4 = 0.057

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K_c=\frac{[NO_2]^2}{[N_2O_4]}

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Putting values in above expression, we get:

K_c=\frac{(0.286)^2}{0.143}\\\\K_c=1.435

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