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galina1969 [7]
3 years ago
7

Americium-241 is a radioactive substance used in smoke detectors. The half life of americium is 432 years. If a smoke detector i

nitially contains 1 gram of Americium 241, how much will remain in 432 years? A) 0.5g B) 1.0g C) 1.5g D) 2.0g
Chemistry
1 answer:
aksik [14]3 years ago
7 0
<span>The half life of americium is 432 years. That means that after 432 years only half(1/2) of initial amount will be left.
If we had 1 g, then after 432 years we will have only half of it.
1g*1/2=1/2 g=0.5 g
Answer is </span><span>A) 0.5g</span>
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Answer:18652.5

Explanation

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3 years ago
You have 55 grams of glucose(C6H12O6). How many grams of oxygen do you have?
zubka84 [21]

Answer:

Mass of oxygen in glucose = 29.3g

Explanation:

Mass of glucose given is 55grams.

We are to find the mass of oxygen in this compound.

In the compound we have 6 atoms of oxygen.

Solution

To find the mass of oxygen in glucose, we calculate the formula mass of glucose. We now divide the formula mass of the oxygen atom with that of the glucose and multiply by the given mass to find the unkown mass.

Atomic mass of C = 12g

                           H = 1g

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Formula mass of C₆H₁₂O₆ = {(12x6) + (1x12) + (16x6)} = 180

             Mass of O in glucose = \frac{6x16}{180}  x 55

                                                  = \frac{96}{180} x 55

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8 0
3 years ago
I WILL GIVE 50 POINTS AND BRAINLIEST What is the volume of 41.2g argon at stp???
iragen [17]

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1645.86

Explanation:

4 0
3 years ago
Represent the decomposition of aluminum oxide using the same number of atoms of molecules as are
pantera1 [17]

Answer:

Decomposition of aluminium oxide forms  aluminium atoms and  oxygen atoms.

Explanation:

<u>Decomposition reaction:</u>

When a single compound break down into two or more simpler products.

For example "AB" reactant undergoes decomposition to form "A" and "B" products.

The chemical reaction is as follows.

AB\rightarrow A+B

The given compound is aluminium oxide.

The decomposition reaction of aluminium oxide is a follows.

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The balanced equation is as follows.

2Al_{2}O_{3}\rightarrow 4Al+3O_{2}

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4 0
3 years ago
A stock solution of FeCl2 is available to prepare solutions that are more dilute. Calculate the volume, in mL, of a 2.0-M soluti
Harman [31]

Answer:

31.5mL

Explanation:

The following were obtained from the question:

C1 (concentration of stock solution) = 2M

V1 (volume of stock solution) =.?

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Using the dilution formula C1V1 = C2V2, the volume of the stock solution needed can be obtained as follow:

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Divide both side by 2

V1 = (0.630 x 100) /2

V1 = 31.5mL

Therefore, 31.5mL of 2M solution of FeCl2 required

7 0
3 years ago
Read 2 more answers
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