There's no such thing as "an unbalanced force".
If all of the forces acting on an object all add up to zero, then we say that
<span>the group </span>of forces is balanced. When that happens, the group of forces
has the same effect on the object as if there were no forces on it at all.
An example:
Two people with exactly equal strength are having a tug-of-war. They pull
with equal force in opposite directions. Each person is sweating and straining,
grunting and groaning, and exerting tremendous force. But their forces add up
to zero, and the rope goes nowhere. The <u>group</u> of forces on the rope is balanced.
On the other hand, if one of the offensive linemen is pulling on one end of
the rope, and one of the cheerleaders is pulling on the other end, then their
forces don't add up to zero, because even though they're opposite, they're
not equal. The <u>group</u> of forces is <u>unbalanced</u>, and the rope moves.
A group of forces is either balanced or unbalanced. A single force isn't.
The Answer is Option C
I think...
Sorry If i am wrong...
-- There are three pairs of mass with gravitational forces between them.
-- The distances between the masses are the same for each pair.
-- The only other quantity that determines the strength of the gravitational
force is the product of the masses.
-- The product of the masses is greatest for the apple and the watermelon,
so the strength of the gravitational force between them is the greatest.
At time t = 0 the velocity is v1. Therefore C1 = v1 and C2 = x1. Equations (1), (2), (3), and (4) fully describe the motion of particles, or bodies experiencing rectilinear (straight-line) motion, where acceleration a is constant.
