The amount of work done in emptying the tank by pumping the water over the top edge is 163.01* 10³ ft-lbs.
Given that, the tank is 8 feet across the top and 6 feet high
By the property of similar triangles, 4/6 = r/y
6r = 4y
r = 4/6*y = 2/3*y
Each disc is a circle with area, A = π(2/3*y)² = 4π/9*y²
The weight of each disc is m = ρw* A
m = 62.4* 4π/9*y² = 87.08*y²
The distance pumped is 6-y.
The work done in pumping the tank by pumping the water over the top edge is
W = 87.08 ∫(6-y)y² dy
W = 87.08 ∫(6y³ - y²) dy
W = 87.08 [6y⁴/4 - y³/3]
W = 87.08 [3y⁴/2- y³/3]
The limits are from 0 to 6.
W = 87.08 [3*6⁴/2 - 6³/3] = 87.08* [9*6³ - 2*36] = 87.08(1872) = 163013.76 ft-lbs
The amount of work done in emptying the tank by pumping the water over the top edge is 163013.76 ft-lbs.
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Answer:
700 watts
Explanation:
From the question, it is given that;
Force = 700N
Distance = 6m
Time = 6s
<u>First step:</u> we derive the formula that relates Power, distance and time, from first principle

But Energy is Force X Distance


Power = 700 watts
The power you will lose after walking the stairs is 700 watts
Answer is B, it can be positive or negative, as long as it has a charge.
Answer:
The correct option is d: T₁ > T₂ > T₃.
Explanation:
Let's evaluate each tension.
<u>Case T₃.</u>

For the system to be in equilibrium, the algebraic sum of the tension force (T) and the weight (W) must be equal to zero. The minus sign of W is because it is in the opposite direction of T.
Since W₃ = mg, where <em>m</em> is for mass and <em>g</em> is for the acceleration due to gravity, we have:
(1) <u>Case T₂.</u>
(2)
By entering W₂ = 2mg and equation (1) into eq (2) we have:
<u>Case T₁.</u>
(3)
Knowing that W₁ = 3mg and T₂ = 3mg, eq (3) is:
Therefore, the correct option is d: T₁ > T₂ > T₃.
I hope it helps you!
<span>It takes only one atom to make hydrogen; however, hydrogen is commonly found as H2, meaning two atoms make up hydrogen. Because of this, hydrogen is known as a diatomic element
The answer is prob A.1 but you didnt' give me a formula.</span>