Question

Many species cool themselves by sweating, because as the sweat evaporates, heat is transferred to the surroundings. A human exercising strenuously has an evaporative heat loss rate of about 657 W. If a person exercises strenuously for 28.6 min, how much water must he drink to replenish his fluid loss? The heat of vaporization of water is 2430 J/g at normal skin temperature.

Answer 1

Answer:

The water lost is 463.95 g.

Explanation:

Given that,

Heat lost rate = 657 W

Time = 28.6 min

Heat vaporization = 2430 J/g

We need to calculate the heat lost

Using formula of heat loss

$heat\ lost =657\times28.6\times60$

$heat\ lost=1127412\ J$

We need to calculate the water lost

Using formula of water lost

$water\ lost=\dfrac{heat\ lost}{heat\ vaporization}$

Put the value into the formula

$water\ lost=\dfrac{1127412}{2430}$

$water\ lost=463.95\ g$

Hence, The water lost is 463.95 g.