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3 years ago

At the particle level, the weakest of the fundamental forces is:

Physics

2 answers:

Anna [14]3 years ago

7 0

Answer:

GRAVITY

Explanation:

There are four fundamental forces in nature

1). Gravitational force

2). Electromagnetic force

3). Strong Nuclear Force

4). Weak Nuclear Force

So here out of all above forces the strongest force is nuclear force which only depends on the distance between the nucleons while the weakest force among all is gravitational force which depends on the mass of two bodies and distance between them.

Gravitational force is a long range force so it exist upto the large distance while nuclear force is a short range force and could not exist for large distance which is more than 1 fermi.

So here correct answer will be

Gravity

marshall27 [118]3 years ago

3 0

It should be gravity.

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What is the total kinetic energy of a 0.15 kg hockey puck sliding at 0.5 m/s and rotating about its center at 8.4 rad/s

AlexFokin [52]

Answer:

$K=0.023J$

Explanation:

From the question we are told that:

Mass $m=0.15$

Velocity $v=0.5m/s$

Angular Velocity $\omega=8.4rad/s$

Generally the equation for Kinetic Energy is mathematically given by

$K=\frac{1}{2}M(v^2+\frac{1}{2}R^2\omega^2)$

$K=\frac{1}{2}0.15(0.5^2+\frac{1}{2}(0.038)^2.(8.4rad/s^2))$

$K=0.023J$

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2 years ago

Using at least 3 to 4 complete content related sentences describe the first and second postulate of special relativity.

Andrew [12]

Nothing can travel faster than the speed of light. As such, perceptions of objects and time change as they approach light speed, but the laws of physics remain consistent regardless of speed. Objects will appear shortened and time will appear to slow down around an observer approaching near light speeds, but all quantities still exist as they did before and all causality is preserved, even if observers in different points or traveling at different speeds will report different things.

8 0

3 years ago

Read 2 more answers

A ball with a mass of 2000 g is floating on the surface of a pool of water. What is the minimum volume that the ball could have

Doss [256]

Answer:

$2000\; {\rm cm^{3}}$ .

Explanation:

When the ball is placed in this pool of water, part of the ball would be beneath the surface of the pool. The volume of the water that this ball displaced is equal to the volume of the ball that is beneath the water surface.

The buoyancy force on this ball would be equal in magnitude to the weight of water that this ball has displaced.

Let $m(\text{ball})$ denote the mass of this ball. Let $m(\text{water})$ denote the mass of water that this ball has displaced.

Let $g$ denote the gravitational field strength. The weight of this ball would be $m(\text{ball}) \, g$ . Likewise, the weight of water displaced would be $m(\text{water})\, g$ .

For this ball to stay afloat, the buoyancy force on this ball should be greater than or equal to the weight of this ball. In other words:

$\text{buoyancy} \ge m(\text{ball})\, g$ .

At the same time, buoyancy is equal in magnitude the the weight of water displaced. Thus:

$\text{buoyancy} = m(\text{water}) \, g$ .

Therefore:

$m(\text{water})\, g = \text{buoyancy} \ge m(\text{ball})\, g$ .

$m(\text{water}) \ge m(\text{ball})$ .

In other words, the mass of water that this ball displaced should be greater than or equal to the mass of of the ball. Let $\rho(\text{water})$ denote the density of water. The volume of water that this ball should displace would be:

$\begin{aligned}V(\text{water}) &= \frac{m(\text{water})}{\rho(\text{water})} \\ &\ge \frac{m(\text{ball}))}{\rho(\text{water})} \end{aligned}$ .

Given that $m(\text{ball}) = 2000\; {\rm g}$ while $\rho = 1.00\; {\rm g\cdot cm^{-3}}$ :

$\begin{aligned}V(\text{water}) &\ge \frac{m(\text{ball}))}{\rho(\text{water})} \\ &= \frac{2000\; {\rm g}}{1.00\; {\rm g\cdot cm^{-3}}} \\ &= 2000\; {\rm cm^{3}}\end{aligned}$ .

In other words, for this ball to stay afloat, at least $2000\; {\rm cm^{3}}$ of the volume of this ball should be under water. Therefore, the volume of this ball should be at least $2000\; {\rm cm^{3}}\!$ .

3 0

2 years ago

During a shock which lasts 10ms (0.01s), the voltage difference between the electrodes (so the drop in potential across all thre

natta225 [31]

Answer:

20000 W

Explanation:

Power: This can be defined as the rate at which energy is dissipated or used. The S.I unit of power is Watt(W).

The expression of power is given as,

P = E/t.............................. Equation 1

Where P = power, E = Energy, t = time.

Given: E = 200 J, t = 0.01 s

Substitute into equation 1

P = 200/0.01

P = 20000 W.

Hence the average power = 20000 W

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3 years ago

Which of the following is the correct formula for sulfur hexaflouride? SF 6 SF 5 SF 8 SF

alexira [117]

Answer: SF6

Explanation: Hexa is a prefix means 6. Sulfur Hexafluoride is expressed in SF6

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3 years ago