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3 years ago

At the particle level, the weakest of the fundamental forces is:

Physics

2 answers:

Anna [14]3 years ago

7 0

Answer:

GRAVITY

Explanation:

There are four fundamental forces in nature

1). Gravitational force

2). Electromagnetic force

3). Strong Nuclear Force

4). Weak Nuclear Force

So here out of all above forces the strongest force is nuclear force which only depends on the distance between the nucleons while the weakest force among all is gravitational force which depends on the mass of two bodies and distance between them.

Gravitational force is a long range force so it exist upto the large distance while nuclear force is a short range force and could not exist for large distance which is more than 1 fermi.

So here correct answer will be

Gravity

marshall27 [118]3 years ago

3 0

It should be gravity.

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According to the what the universe's total amount of energy does not change

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The Law of Conservation of Energy

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3 years ago

John flies directly east for 20km, then turns to the north and flies for another 10 km before dodging a flock of geese. what’s t

KIM [24]

The distance is 30 km and the displacement is 22.4 km North East

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3 years ago

A piston–cylinder assembly contains 5.0 kg of air, initially at 2.0 bar, 30 oF. The air undergoes a process to a state where the

vladimir2022 [97]

Answer:

The work and heat transfer for this process is = 270.588 kJ

Explanation:

Take properties of air from an ideal gas table. R = 0.287 kJ/kg-k

The Pressure-Volume relation is PV = C

T = C for isothermal process

Calculating for the work done in isothermal process

W = P₁V₁ $ln[\frac{P_{1} }{P_{2} }]$

= mRT₁ $ln[\frac{P_{1} }{P_{2} }]$ [∵pV = mRT]

= (5) (0.287) (272.039) $ln[\frac{2.0}{1.0}]$

= 270.588 kJ

Since the process is isothermal, Internal energy change is zero

ΔU = $mc_{v}(T_{2} - T_{1} ) = 0$

From 1st law of thermodynamics

Q = ΔU + W

= 0 + 270.588

= 270.588 kJ

4 0

3 years ago

Please answer the question

AfilCa [17]

The answer is Cㅤㅤㅤㅤㅤ

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3 years ago

12) Water flows through a horizontal pipe of cross-sectional area 10.0 cm2 at a pressure of 0.250 atm with a flow rate is 1.00 L

masha68 [24]

Answer:

The pressure after passing the valve is 23,8 [Kpa] ( 0,234 atm) and the pressure drop is about 1,53 [Kpa]

Explanation:

We need to use the formula of bernoulli, in the attached image we can see the fluid throw the pipe, we also can calculate the velocity inside the pipe using the flow rate and the cross sectional area.

For this case, we don't use the elevation difference and therefore those terms can be cancelled.

When the area has reduced the velocity of the fluid is increased but there is a drop pressure through the valve.

5 0

3 years ago