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harkovskaia [24]

3 years ago

7

A 2kg body is moving a long a horizontal circular path of radius 2m with constant speed of 6m/s . what is the magnitude of the f

orce acting on the body ?

1 answer:

kondor19780726 [428]3 years ago

7 0

The magnitude of force acting on the body is 36N

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A hot metal bolt of mass 0.06 kg and specific heat capacity 899 J/kg°C is dropped into a calorimeter containing 0.16 kg water at

skad [1K]

Answer:

Explanation:

Given

mass of hot metal $m_1=0.06\ kg$

specific heat $c=889\ J/kg-^{\circ}C$

mass of water $m_2=0.16\ kg$

Temperature pf water $T_2=20^{\circ}C$

Final Temperature $T=25^{\circ}C$

let $T_1$ be the temperature of hot metal ball

Heat lost by heat metal bolt is gained by water in calorimeter

Heat lost by hot metal bolt $Q_1=m\times c\times \Delta T$

$Q_1=0.06\times 889\times (T-25)$

Heat gained by water $Q_2=m_2\times c_w\times \Delta T$

$Q_2=0.16\times 4184\times (25-20)$

$Q_1=Q_2$

$0.06\times 889\times (T-25)=0.16\times 4184\times (25-20)$

$T_1=25+62.75$

$T_1=87.75^{\circ}C$

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3 years ago

The highest waterfall in the world is the Salto Angel in Venezuela. Its longest single falls has a height of 807 m. If water at

valentina_108 [34]

Answer:

Temperature at the bottom will be 19.18°C

Explanation:

We have given height h = 807 m

Temperature at the top $=17.3^{\circ}C$

Specific heat of water c = 4200 $J/kg/^{\circ}C$

From energy conservation

Kinetic energy at the bottom = potential energy at the top

So $mc\Delta T=mgh$

$\Delta T=\frac{gh}{c}=\frac{9.8\times 807}{4200}=1.88^{\circ}C$

So temperature at the bottom = 17.3+1.88 = 19.18°C

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