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harkovskaia [24]

2 years ago

7

A 2kg body is moving a long a horizontal circular path of radius 2m with constant speed of 6m/s . what is the magnitude of the f

orce acting on the body ?

1 answer:

kondor19780726 [428]2 years ago

7 0

The magnitude of force acting on the body is 36N

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Dos cargas puntuales q1 = −50μC y q2 = +30μC se encuentran

alina1380 [7]

Answer:

Datos:

q1 = -50 μC = $50*10^{-6}$

q2 = +30 μC = $30*10^{-6}$

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a) x si la <em>F = 10N</em>

Aplicando la Ley de Coulomb:

x = $\sqrt\frac{k0 * q1 *q2}{F}$ = $\sqrt\frac{(9*10^{9} )*(50*10^{-6})*(30*10^{-6})}{10}$ = 1,162m

b) x si la <em>F = 20 N</em>

x=<em> </em> $\sqrt\frac{(9*10^{9} )*(50*10^{-6})*(30*10^{-6})}{20}$ <em> </em>= 0,822m

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