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3 years ago

The increase in resistant strains of insects to chemicals is a result of:

Physics

1 answer:

trapecia [35]3 years ago

5 0

Answer:

answer D. all of the above

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What is the average velocity of atoms in 2.00 mol of neon (a monatomic gas)

Dimas [21]

Answer:

v = 876 m/s

Explanation:

It is given that,

Number of mol of Neon is 2 mol

Temperature, T = 308 K

Mass, m = 0.02 kg

Value of R - 8.31 J/mol-K

We need to find the average velocity of atoms in 2.00 mol of neon. Neon is a monoatomic gas. Let v is the velocity. So,

$\dfrac{1}{2}mv^2=\dfrac{3}{2}nRT\\\\v=\sqrt{\dfrac{3nRT}{m}} \\\\v=\sqrt{\dfrac{3\times 2\times 8.314\times 308}{0.02}} \\\\v=876.47\ m/s$

So, the correct option is (B).

8 0

2 years ago

Read 2 more answers

How are elements arranged in the modern periodic table?

photoshop1234 [79]

It is currently organised by the increasing atomic # based on the actual nuclear charge of the elements

3 0

3 years ago

Read 2 more answers

At the instant a traffic light turns green, a car starts with a constant acceleration of 1.3 m/s2. At the same instant a truck,

Bas_tet [7]

Answer:

(a) Distance traveled = 75.3846 m

(b) Velocity of car at that instant will be 14 m/sec

Explanation:

We have given acceleration of the car $a=1.3m/sec^2$

Initial velocity of the cart u = 0 m/sec

(a) According to second equation of motion we know that $s=ut+\frac{1}{2}at^2$

So distance traveled by car $s_c=0\times t+\frac{1}{2}\times 1.3t^2=0.65t^2$

As the truck is moving with constant speed

So distance traveled by truck $s_t=ut=7t$

As the truck overtakes the car

So $s_c=s_t$

$0.65t^2=7t$

$t=10.769sec$

So distance traveled $s_c=s_t=7\times 10.769=75.3846m$

(b) From second equation of motion we know that v = u+at

So v = 0+1.3×10.769 = 14 m /sec

7 0

3 years ago

A piece of wire has a resistance of 8 ohms. What

xxMikexx [17]

Answer:

4 ohms

Explanation:

R = PL/A

P is resistivity

L is length and is halved

A cross sectional area, the same so

R = P(L/2)/A = 4

3 0

2 years ago

A medium-sized jet has a 3.8-m-diameter fuselage and a loaded mass of 85,000 kg. The drag on an airplane is primarily due to the

Nataly_w [17]

Answer:

$2.4\times 10^{5} N$

Explanation:

The force of drag is given by

$F= 0.5 C\rho Av^{2}$

C is coefficient of drag

$\rho$ is density of air

A is area which is given by $\frac {\pi d^{2}}{4}$

V is the velocity

$F= 0.5*0.37*1.7\times \frac {\pi 3.8^{2}}{4}\times 260^{2}=2.4\times 10^{5} N$

3 0

3 years ago