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Work done in moving a proton = potential difference×Charge of a proton
= 164×1.6×10⁻¹⁹ = 2.624×10⁻¹⁷ J
This work done should be equal to change in kinetic energy.
Initial speed of proton is zero therefore K.E initial will be zero.
Work done = final kinetic energy = 2.624×10⁻¹⁷ J
K.E = mv²/2
v² = 2(2.624×10⁻¹⁷)/1.6×10⁻²⁷ = 3.28×10¹⁰ m/s
∴ v = 1.811×10⁵ m/s
Answer:
B = (μ₀*i/(2*π*x))*(x²-(a/2)²)/((b/2)²-(a/2)²)
Explanation:
Given
Outer diameter of the wire = b ⇒ R = b/2
Diameter of the clindrical hole at the center = a ⇒ r = a/2
The current that flows from left to right and is uniformly spread over the region between a and b = i
We apply Ampere's Law
Using the following formula for a/2 ≤ x ≤ b/2
B = (μ₀*i/(2*π*x))*(x²-(a/2)²)/((b/2)²-(a/2)²)
Upper mantle
The theory of the plate tectonics uses the convection cells in the upper mantle layer as the foundation for the movement of the continents.
To put it simple the process is explained like the convection cells create a lot of pressure, that pressure, supported by the high temperatures and magma, influence the crust above, and manage to crack it on certain places. As the crust cracks, it becomes a separate entity, and under the enormous force from bellow it slowly moves into a particular direction, and that is actually the movement of the tectonic plates.
Period = 2 seconds.
frequency = 1/2 cycle/second = 1/2 Hz
If it falls twice every four seconds, then it falls once every two seconds, therefore one falling period is two seconds.
Hz is equal to cycles per second. So if it goes through one cycle per two seconds, then it goes through 1/2 cycle per one second.
Hope this helps!
