A bug zapper consists of two metal plates connected to a high-voltage power supply. The voltage between the plates is set to giv
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Answer:
a) W = 46.8 J and b) v = 3.84 m/s
Explanation:
The energy work theorem states that the work done on the system is equal to the variation of the kinetic energy
W = ΔK = -K₀
a) work is the scalar product of force by distance
W = F . d
Bold indicates vectors. In this case the dog applies a force in the direction of the displacement, so the angle between the force and the displacement is zero, therefore, the scalar product is reduced to the ordinary product.
W = F d cos θ
W = 39.0 1.20 cos 0
W = 46.8 J
b) zero initial kinetic language because the package is stopped
W - =
-K₀
W - fr d= ½ m v² - 0
W - μ N d = ½ m v
on the horizontal surface using Newton's second law
N-W = 0
N = W = mg
W - μ mg d = ½ m v
v² = (W -μ mg d) 2/m
v = √(W -μ mg d) 2/m
v = √[(46.8 - 0.30 4.30 9.8 1.20) 2/4.3 ]
v = √(31.63 2/4.3)
v = 3.84 m/s
The solution of Sulfuric Acid (H2SO4) has the following mole fractions:
- mole fraction (H2SO4)= 0.034
- mole fraction (H2O)= 0.966
To solve this problem the formula and the procedure that we have to use is:
- n = m / MW
- = ∑ AWT
- mole fraction = moles of A component / total moles of solution
- ρ = m /v
Where:
- m = mass
- n = moles
- MW = molecular weight
- AWT = atomic weight
- ρ = density
- v = volume
Information about the problem:
- m solute (H2SO4) = 17.75 g
- v(solution) = 100 ml
- ρ (solution)= 1.094 g/ml
- AWT (H)= 1 g/mol
- AWT (S) = 32 g/mol
- AWT (O)= 16 g/mol
- mole fraction(H2SO4) = ?
- mole fraction(H2O) = ?
We calculate the moles of the H2SO4 and of the H2O from the Pm:
MW = ∑ AWT
MW (H2SO4)= AWT (H) * 2 + AWT (S) + AWT (O) * 4
MW (H2SO4)= (1 g/mol * 2) + (32,064 g/mol) + (16 g/mol * 4)
MW (H2SO4)= 2 g/mol + 32 g/mol + 64 g/mol
MW (H2SO4)= 98 g/mol
MW (H2O)= AWT (H) * 2 + AWT (O)
MW (H2O)= (1 g/mol * 2) + (16 g/mol)
MW (H2O)= 2 g/mol + 16 g/mol
MW (H2O)= 18 g/mol
Having the Pm we calculate the moles of H2SO4:
n = m / MW
n(H2SO4) = m(H2SO4) / MW (H2SO4)
n(H2SO4) = 17.75 g / 98 g/mol
n(H2SO4) = 0.1811 mol
With the density and the volume of the solution we get the mass:
ρ(solution)= m(solution) /v(solution)
m(solution) = v(solution) * ρ(solution)
m(solution) = 100 ml * 1.094 g/ml
m(solution) = 109.4 g
Having the mass of the solution we calculate the mass of the water in the solution:
m(H2O) = m(solution) - m solute (H2SO4)
m(H2O) = 109.4 g - 17.75 g
m(H2O) = 91.65 g
We calculate the moles of H2O:
n = m / MW
n(H2O) = m(H2O) / MW (H2O)
n(H2O) = 91.65 g / 18 g/mol
n(H2O) = 5.092 mol
We calculate the total moles of solution:
total moles of solution = n(H2SO4) + n(H2O)
total moles of solution = 0.1811 mol + 5.092 mol
total moles of solution = 5.2731 mol
With the moles of solution we can calculate the mole fraction of each component:
mole fraction (H2SO4)= moles of (H2SO4) / total moles of solution
mole fraction (H2SO4)= 0.1811 mol / 5.2731 mol
mole fraction (H2SO4)= 0.034
mole fraction (H2O)= moles of (H2O) / total moles of solution
mole fraction (H2O)= 5.092 mol / 5.2731 mol
mole fraction (H2O)= 0.966
<h3>What is a solution?</h3>In chemistry a solution is known as a homogeneous mixture of two or more components called:
- Solvent
- Solute
Learn more about chemical solution at: brainly.com/question/13182946 and brainly.com/question/25326161
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