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Bas_tet [7]
3 years ago
13

A bug zapper consists of two metal plates connected to a high-voltage power supply. The voltage between the plates is set to giv

e an electric field slightly less than 1×10⁶ V/m . When a bug flies between the two plates, it increases the field enough to initiate a spark that incinerates the bug.
If a bug zapper has a 7000 V power supply, what is the approximate separation between the plates?
(a) 7×10⁻² cm
(b) 0.7 cm
(c) 7 cm
(d) 70 cm
Physics
1 answer:
Allisa [31]3 years ago
4 0

Answer:

(b) 0.7 cm

Explanation:

E = Electric field = 1\times 10^6\ V/m

V = Voltage = 7000 V

d = Seperation between the plates

Electric field is given by

E=\dfrac{V}{d}

\\\Rightarrow d=\dfrac{V}{E}\\\Rightarrow d=\dfrac{7000}{1\times 10^6}\\\Rightarrow d=0.007\ m=0.7\ cm

The approximate separation between the plates is 0.7 cm

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Joe is measuring the time it takes for a ball to roll down a ramp. In this experiment Joe takes the measurement 5 times and gets
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 Step by step solution :

standard deviation is given by :

\sigma = \sqrt\dfrac{{\sum (x-\bar{x})^2}}{n}

where, \sigma is standard deviation

\bar{x} is mean of given data

n is number of observations

From the above data, \bar{x}=24.88

Now, if x=24.8, then (x-\bar{x})^2=0.0064

If  x=23.9, then (x-\bar{x})^2=0.9604

if x=26.1, then (x-\bar{x})^2=1.4884

If x=25.1, then (x-\bar{x})^2=0.0484

If x=24.5, then (x-\bar{x})^2=0.1444

so, \sum (x-\bar{x})^2 =\frac{0.0064+0.9604+1.4884+0.0484+0.1444}{5}

\sum (x-\bar{x})^2 =2.648

\sqrt{\sum \frac{(x-\bar{x})^2}{n}}

\sigma =0.7277

No, Joe's value does not agree with the accepted value of 25.9 seconds. This shows a lots of errors.

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A(n)............ exerts a force on a system. It is symbolised as a subscript to the force.
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I’ve already figured out A. I just need help with B and C.
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