He gave away 14 bouncy balls
Answer:
25 ft if i am right than u plss mark me as brainliest
Answer:
2a). Y= 1. 3= x
2b). Y=4 x= 1
3).
Y= x²+3x-18
For -5
First difference
10
Second difference
-8
For -4
First difference
4
Second difference
-14
For -3
First difference
9-9= 0
Second difference
-18
For -2
First difference
-2
Second difference
-20
For -1
First difference
-2
Second difference
-20
For 0
First difference
0
Second difference
-18
The relation ia a quadratic relation because of the highest Power of x to be 2
Step-by-step explanation:
For
Y=- x+4. Y= 1
Y=x-2. 1= x-2
2y =2. 1+2= x
Y= 1. 3= x
For
Y= x+3. 1= x
Y= 3x+1. Y= 3+1
0= 2x-2. Y= 4
2= 2x
1= x
Y= x²+3x-18
For -5
First difference
25-15= 10
Second difference
10-18= -8
For -4
First difference
16-12= 4
Second difference
4-18= -14
For -3
First difference
9-9= 0
Second difference
0-18 = -18
For -2
First difference
4-6= -2
Second difference
-2-18= -20
For -1
First difference
1-3 = -2
Second difference
-2-18 = -20
For 0
First difference
0+0 = 0
Second difference
0 -18= -18
The relation ia a quadratic relation because of the highest Power of x to be 2
Answer:
![R=(\dfrac{b}{2},0)](https://tex.z-dn.net/?f=R%3D%28%5Cdfrac%7Bb%7D%7B2%7D%2C0%29)
![S=(\dfrac{b+c}{2},\dfrac{d}{2})](https://tex.z-dn.net/?f=S%3D%28%5Cdfrac%7Bb%2Bc%7D%7B2%7D%2C%5Cdfrac%7Bd%7D%7B2%7D%29)
![T=(\dfrac{c+e}{2},\dfrac{d+f}{2})](https://tex.z-dn.net/?f=T%3D%28%5Cdfrac%7Bc%2Be%7D%7B2%7D%2C%5Cdfrac%7Bd%2Bf%7D%7B2%7D%29)
![U=(\dfrac{e}{2},\dfrac{f}{2})](https://tex.z-dn.net/?f=U%3D%28%5Cdfrac%7Be%7D%7B2%7D%2C%5Cdfrac%7Bf%7D%7B2%7D%29)
![M=(\dfrac{b+c+e}{4},\dfrac{d+f}{4})](https://tex.z-dn.net/?f=M%3D%28%5Cdfrac%7Bb%2Bc%2Be%7D%7B4%7D%2C%5Cdfrac%7Bd%2Bf%7D%7B4%7D%29)
![M=(\dfrac{c+b+e}{4},\dfrac{d+f}{4})](https://tex.z-dn.net/?f=M%3D%28%5Cdfrac%7Bc%2Bb%2Be%7D%7B4%7D%2C%5Cdfrac%7Bd%2Bf%7D%7B4%7D%29)
Step-by-step explanation:
We are given coordinates as:
![A(0,0)\ ,\ B=(b,0)\ ,\ C=(c,d)\ ,\ D=(e,f)\\\\R=(\dfrac{b}{2},0)\ ,\ S=(\dfrac{b+c}{2},\dfrac{d}{2})\ ,\ U=(\dfrac{e}{2},\dfrac{f}{2})\ ,\ T=(\dfrac{c+e}{2},\dfrac{d+f}{2})](https://tex.z-dn.net/?f=A%280%2C0%29%5C%20%2C%5C%20B%3D%28b%2C0%29%5C%20%2C%5C%20C%3D%28c%2Cd%29%5C%20%2C%5C%20D%3D%28e%2Cf%29%5C%5C%5C%5CR%3D%28%5Cdfrac%7Bb%7D%7B2%7D%2C0%29%5C%20%2C%5C%20S%3D%28%5Cdfrac%7Bb%2Bc%7D%7B2%7D%2C%5Cdfrac%7Bd%7D%7B2%7D%29%5C%20%2C%5C%20U%3D%28%5Cdfrac%7Be%7D%7B2%7D%2C%5Cdfrac%7Bf%7D%7B2%7D%29%5C%20%2C%5C%20T%3D%28%5Cdfrac%7Bc%2Be%7D%7B2%7D%2C%5Cdfrac%7Bd%2Bf%7D%7B2%7D%29)
Now, it is given that M is the mid-point of the line segment RT and of US.
Hence, the coordinates of M is given as:
By taking the mid-point of side RT.
![M=(\dfrac{\dfrac{b}{2}+\dfrac{c+e}{2}}{2},\dfrac{0+\dfrac{d+f}{2}}{2}})\\\\\\i.e.\\\\\\M=(\dfrac{b+c+e}{4},\dfrac{d+f}{4})](https://tex.z-dn.net/?f=M%3D%28%5Cdfrac%7B%5Cdfrac%7Bb%7D%7B2%7D%2B%5Cdfrac%7Bc%2Be%7D%7B2%7D%7D%7B2%7D%2C%5Cdfrac%7B0%2B%5Cdfrac%7Bd%2Bf%7D%7B2%7D%7D%7B2%7D%7D%29%5C%5C%5C%5C%5C%5Ci.e.%5C%5C%5C%5C%5C%5CM%3D%28%5Cdfrac%7Bb%2Bc%2Be%7D%7B4%7D%2C%5Cdfrac%7Bd%2Bf%7D%7B4%7D%29)
By taking the mid-point of side US.
![M=(\dfrac{\dfrac{e}{2}+\dfrac{b+c}{2}}{2},\dfrac{\dfrac{f}{2}+\dfrac{d}{2}}{2})\\\\\\i.e.\\\\\\M=(\dfrac{b+c+e}{4},\dfrac{d+f}{4})](https://tex.z-dn.net/?f=M%3D%28%5Cdfrac%7B%5Cdfrac%7Be%7D%7B2%7D%2B%5Cdfrac%7Bb%2Bc%7D%7B2%7D%7D%7B2%7D%2C%5Cdfrac%7B%5Cdfrac%7Bf%7D%7B2%7D%2B%5Cdfrac%7Bd%7D%7B2%7D%7D%7B2%7D%29%5C%5C%5C%5C%5C%5Ci.e.%5C%5C%5C%5C%5C%5CM%3D%28%5Cdfrac%7Bb%2Bc%2Be%7D%7B4%7D%2C%5Cdfrac%7Bd%2Bf%7D%7B4%7D%29)
The change of base formula looks like this:
log x
(log to the base b of ) x = ----------- (you could also use ln instead of log)
log b
log 40 1.602
Then (log to the base 7 of) 40 = ------------ = ------------- = 1.896 (answer)
log 7 0.8451
check (on calculator): 7^1.896 = 40.023 (close enough to 40 to verify
that this method "worked")