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almond37 [142]
3 years ago
14

How much work is accomplished when a force of 400 N pushes a box across the floor for a distance of 10 meters?

Physics
1 answer:
gizmo_the_mogwai [7]3 years ago
6 0
Formulae is work=f×d
                           =400n×10m
                            =4000joules
so the answer is b.4000joules
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A concept is the general idea of objects, events, animals, or people based on common features, traits, or characteristics.
salantis [7]

Answer:

True.

Explanation:

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7 0
3 years ago
How does the de broglie wavelength of an electron change if its momentum increases?
Virty [35]

Answer:

The De Broglie wavelength decreases

Explanation:

The relationship between the De Broglie wavelength of a particle and its momentum is given by

\lambda=\frac{h}{p}

where

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h is the Planck constant

p is the momentum of the particle

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and vice-versa.

3 0
3 years ago
A train travels 59 kilometers in 3 hours, and then 74 kilometers in 5 hours. What is its average speed?
dybincka [34]
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3 0
3 years ago
7. A roller coaster’s velocity at the top of a hill is 10 m/s. Two seconds later it reaches the bottom ofthe hill with a velocit
zheka24 [161]

Answer:

7) a=8m/s^2

8) a=-5m/s^2

9) a=-1.5m/s^2

10) v=29.4m/s

Explanation:

For the problems 7, 8 and 9 we just apply the definition of acceleration, since no more information is given, which is:

a=\frac{\Delta v}{\Delta t}=\frac{v_f-v_i}{t_f-t_i}

So for each problem we will have:

7) a=\frac{26m/s-10m/s}{2s}=8m/s^2

8) a=\frac{10m/s-25m/s}{3s}=-5m/s^2

9) a=\frac{0m/s-15m/s}{10s}=-1.5m/s^2

For the problem 10, we use the equation of velocity in accelerated motion:

v=v_0+at

Since the ball starts from rest and the acceleration is that of gravity (we take the downward direction positive), we have:

v=(0m/s)+(9.8m/s)(3s)=29.4m/s

5 0
3 years ago
An applied pulling force of 100 N is used to accelerate an object to the right along a rough surface that offers 40 N of frictio
blondinia [14]

Answer:

9.8 m/s^2

Explanation:

First of all, we analyze the vertical direction.

Along this direction, the object is in equilibrium, so its acceleration is zero, and therefore  the net force on it is zero. There are only two forces acting on the object vertically: the weight, W (downward), and the normal force, N (upward), and since the net force must be zero, we can write

W=N

And since N = 60 N, the weight of the object is

W = 60 N

From this, we can also find the mass of the object, using the equation:

W=mg \rightarrow m = \frac{W}{g}=\frac{60}{9.8}=6.1 kg

where g=9.8 m/s^2 is the acceleration of gravity.

Now we analyze the forces along the horizontal direction. We have:

A pulling force of F=100 N forward

A frictional resistance of F_f = 40 N backward

So the equation of motion in this direction is

F-F_f = ma

And solving for a, we find the acceleration of the object:

a=\frac{F-F_f}{m}=\frac{100-40}{6.1}=9.8 m/s^2

in the horizontal direction, forward.

4 0
3 years ago
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