Answer:
(4xy+5ab)(4xy-5ab)
Explanation:
16![x^{2}](https://tex.z-dn.net/?f=x%5E%7B2%7D)
-25![a^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D)
![b^{2}](https://tex.z-dn.net/?f=b%5E%7B2%7D)
4^2 is 16 and 5^2 is 25,
Also, (x-a)(x+a) = x^2-a^2
So, this factorized is:
(4xy+5ab)(4xy-5ab)
Hope this helps!
1) The equivalent resistance of two resistors in parallel is given by:
![\frac{1}{R_{eq}}= \frac{1}{R_1}+ \frac{1}{R_2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7BR_%7Beq%7D%7D%3D%20%5Cfrac%7B1%7D%7BR_1%7D%2B%20%5Cfrac%7B1%7D%7BR_2%7D%20%20%20)
so in our problem we have
![\frac{1}{R_{eq}} = \frac{1}{15 \Omega}+ \frac{1}{40 \Omega}=0.092 \Omega^{-1}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7BR_%7Beq%7D%7D%20%3D%20%20%5Cfrac%7B1%7D%7B15%20%5COmega%7D%2B%20%5Cfrac%7B1%7D%7B40%20%5COmega%7D%3D0.092%20%5COmega%5E%7B-1%7D%20%20%20)
and the equivalent resistance is
![R_{eq} = \frac{1}{0.092 \Omega^{-1}}=10.9 \Omega](https://tex.z-dn.net/?f=R_%7Beq%7D%20%3D%20%20%5Cfrac%7B1%7D%7B0.092%20%5COmega%5E%7B-1%7D%7D%3D10.9%20%5COmega%20)
2) If we have a battery of 12 V connected to the circuit, the current in the circuit will be given by Ohm's law, therefore:
Answer:
The wavelength of the EM wave is 7.5 * 10⁻⁴ m
Explanation:
The velocity of a wave is related to its wavelength by the following formula;
velocity = wavelength * frequency
For an electromagnetic (EM) wave, its velocity is equal to the velocity of light, c = 3.0 * 10⁸ m/s
Given that the frequency and veloity of the given EM wave in the question is known, its wavelength is calculated as follows:
wavelength = velocity/frequency
where velocity of the EM wave = 3.0 * 10⁸ m/s;
frequency = 4THz = 4 * 10¹² Hz
wavelength = 3.0 * 10⁸m/s / 4 * 10¹² Hz
wavelength = 7.5 * 10⁻⁴ m
Therefore, the wavelength of the EM wave is 7.5 * 10⁻⁴ m